Question

我在尝试将日志文件从Azure Batch执行持久保存到Azure Blob存储时遇到以下错误-“ FileUploadMiscError-上载输出文件之一时遇到其他错误”。此错误不会提供很多有关可能出问题的信息。我尝试检查Microsoft文档中的此错误代码，但未提及此特定错误代码。下面是用于将任务添加到Azure批处理的相关代码，我已将其从C＃移植到Python以持久保存日志文件。

注意：添加任务时会创建我配置的容器，但是里面没有斑点。

import datetime
import logging
import os

import azure.storage.blob.models as blob_model
import yaml
from azure.batch import models
from azure.storage.blob.baseblobservice import BaseBlobService
from azure.storage.common.cloudstorageaccount import CloudStorageAccount
from dotenv import load_dotenv

LOG = logging.getLogger(__name__)


def add_tasks(batch_client, job_id, task_id, io_details, blob_details):

    task_commands = "This is a placeholder. Actual code has an actual task. This gets completed successfully."

    LOG.info("Configuring the blob storage details")
    base_blob_service = BaseBlobService(
        account_name=blob_details['account_name'],
        account_key=blob_details['account_key'])
    LOG.info("Base blob service created")

    base_blob_service.create_container(
        container_name=blob_details['container_name'], fail_on_exist=False)
    LOG.info("Container present")

    container_sas = base_blob_service.generate_container_shared_access_signature(
        container_name=blob_details['container_name'],
        permission=blob_model.ContainerPermissions(write=True),
        expiry=datetime.datetime.now() + datetime.timedelta(days=1))
    LOG.info(f"Container SAS created: {container_sas}")

    container_url = base_blob_service.make_container_url(
        container_name=blob_details['container_name'], sas_token=container_sas)
    LOG.info(f"Container URL created: {container_url}")

    # fpath = task_id + '/output.txt'
    fpath = task_id

    LOG.info(f"Creating output file object:")
    out_files_list = list()

    out_files = models.OutputFile(
        file_pattern=r"../stderr.txt",
        destination=models.OutputFileDestination(
            container=models.OutputFileBlobContainerDestination(
                container_url=container_url, path=fpath)),
        upload_options=models.OutputFileUploadOptions(
            upload_condition=models.OutputFileUploadCondition.task_completion))

    out_files_list.append(out_files)
    LOG.info(f"Output files: {out_files_list}")

    LOG.info(f"Creating the task now: {task_id}")
    task = models.TaskAddParameter(
        id=task_id, command_line=task_commands, output_files=out_files_list)

    batch_client.task.add(job_id=job_id, task=task)
    LOG.info(f"Added task: {task_id}")

Answer 1

批处理的OutputFile处理中存在一个错误，如果完整的容器URL包含除SAS令牌中所包含的查询字符串以外的任何查询字符串参数，都会导致其无法上传到容器。不幸的是，azure-storage-blob Python模块在通过make_container_url生成URL时包含一个额外的查询字符串参数。

这个问题刚刚提出来，我们将在接下来的几周内发布修复程序，但是一个简单的解决方法是使用make_container_url来制作URL，而不是使用{{1} }。

生成的URL应该如下所示：container_url = 'https://{}/{}?{}'.format(blob_service.primary_endpoint, blob_details['container_name'], container_sas)-特别是它不应包含https://<account>.blob.core.windows.net/<container>?se=2019-01-12T01%3A34%3A05Z&sp=w&sv=2018-03-28&sr=c&sig=<sig>（这是restype=container软件包所包含的内容）

保留Azure Batch的输出文件时出现FileUploadMiscError

1 个答案: