Question

我已输入XML作为country.xml：-

<root>
<set>
    <name>US</name>
    <stringval>New York</stringval>
</set>
<set>
    <name>UK</name>
    <integerval>12</integerval>
</set>
</root>

我正在解析xml并将其放入列表中，并且我有一个字典，基于该字典我可以比较和添加xml元素。

diction: dict = {'US':'Chicago', 'UK':'London'}
source = etree.getroot()
for key,value in diction.items()
    countrylist = source.xpath('./set/name[text()=\'{}\']/..'.format(key))
    if len(countrylist) == 0:
        # creating new string and element
        # appending element to original tree
    elif len(countrylist) == 1:   ###This is problematic case what to expect here to update key,value from dictionary only and replace the tag already present in xml
        key = countrylist[0]
        e = ElementMarker()
        stringval = e.stringval
        integerval = e.integerval
        for element in source.findall('./set'):
            name = element.find('name')
            integervalue = element.find('integerval')
            stringvalue = element.find('stringval')
            if stringvalue is None:
                source.clear()
            for val in diction[name.text]:
                source.append(stringval(val))

    else:
        continue

    # writebacktoxml(source,"country.xml")

我得到的输出是原始输入条件，因为它在特定条件下处于输出状态。预期输出如下：-

<root>
<set>
    <name>US</name>
    <stringval>Chicago</stringval>
</set>
<set>
    <name>UK</name>
    <stringval>London</stringval>
</set>
</root>

Answer 1

也许您可以复制XML文件然后进行修改，而且，我认为最好一次迭代XML并与字典进行比较，而不是每次都重复字典并读取XML文件（这可能会导致性能问题）），下面是一个示例：

import xml.etree.ElementTree as ET

xml_file = 'c:/temp/input.xml'
xml_file_output = 'c:/temp/output.xml'
values = {'US': 'Chicago', 'UK': 'London'}

with open(xml_file, 'r') as fin:
    data = fin.read().splitlines(True)
with open(xml_file_output, 'w') as fout:
    fout.writelines(data)

tree = ET.parse(xml_file_output)
xml_root = tree.getroot()

for set in xml_root.iter("set"):
    country = set.find('name').text
    if country in values:
        value = values[set.find('name').text]

        integerval = set.find('integerval')
        if integerval is not None:
            set.remove(integerval)

        stringval = set.find('stringval')
        if stringval is not None:
            set.remove(stringval)

        stringval = ET.Element('stringval')
        stringval.text = value

        set.append(stringval)

tree.write(xml_file_output)

这是输出：

<configroot version="8.0">
    <set>
        <name>US</name>
        <stringval>Chicago</stringval>
    </set>
    <set>
        <name>UK</name>
        <stringval>London</stringval>
    </set>
</configroot>

请注意，如果在词典中找不到国家/地区名称，则不会修改“设置”条目。

如何更新现有的xml元素值和属性？

1 个答案: