Question

尝试使用INNER JOIN函数将id分解为选项值您会协助寻找缺失的东西吗？下面是我的代码：

 <select name="productSize" class="span8 tip" required>
 <?php  $query=mysqli_query($con,"select size.id,size.sizeName from size 
        INNER JOIN products ON size.id=products.productSize where 
        products.id='$pid'");

while($row = mysqli_fetch_assoc($query)) {

    $size = $row['productSize'];
    $boom = explode(",", $size);
    foreach ($boom as $row){
        echo '<option value='.$row['id'].'>'.$row['sizeName'].'</option>'; 
    } ?>
  </select>

更新：感谢大家指出我的错误，下面是更新的代码，其中显示了productSize逗号分隔的ID作为选项值。

  <?php $query=mysqli_query($con,"select size.id, size.sizeName, 
         products.productSize from size INNER JOIN products ON 
         size.id=products.productSize WHERE products.id='$pid'");

         while($row = mysqli_fetch_assoc($query)) {

         $size = $row['productSize'];
         $boom = explode(",", $size);
         foreach ($boom as $row){

          echo '<option value='.$row['id'].'>'.$row['sizeName'].'</option>'; 
             }} ?>

但是仍然存在一个问题：需要显示sizeName而不是ID。附言我是php新手，请原谅我这么简单的问题：）

Answer 1

stages:
  - initialize
  - build

repo1 pull:
  stage: initialize
  script:
    - git clone https://gitlab-ci-token:${CI_JOB_TOKEN}@gitlab.instance/group/repo1.git

repo2 pull:
  stage: initialize
  script:
    - git clone https://gitlab-ci-token:${CI_JOB_TOKEN}@gitlab.instance/group/repo2.git

image1:
  stage: build
  script:
      - cp repo1/ image1/
      - cd image1
      - docker build -t image1 --network=host .
      - docker login -u gitlab-runner -p gitlab docker.registry
      - docker push docker.registry/image1:latest

image2:
  stage: build
  script:
      - cp repo2/ image2/
      - cd image2
      - docker build -t image2 --network=host .
      - docker login -u gitlab-runner -p gitlab docker.registry
      - docker push docker.registry/image2:latest

Answer 2

   <?php
$query=mysqli_query($con,"select size.id, size.sizeName, 
         products.productSize from size INNER JOIN products ON 
         size.id=products.productSize WHERE products.id='$pid'");

         while($row = mysqli_fetch_assoc($query)) {
         ?>
         <option value="<?php echo $row['size.id']; ?>"><?php echo $row['sizeName']; ?>/option>
         <?php


         }
?>

使用INNER JOIN时爆炸

2 个答案: