Question

我试图理解为什么我输入的scores1，score2和scores3
被当作一个字符串。例如：得分1 = 1，得分2 = 1，得分3 =1。平均得分计算为111/3，而不是3/3。

  player1 = prompt(" Welcome Player 1! Please Enter your name ");
  alert(" Hello, " + player1+".");


  p1score1 = prompt(' Enter first score. ');
  p1score2 = prompt(' Enter second score. ');
  p1score3 = prompt(' Enter third score. ');

  /*p1score1 = 89;
  p1score2 = 120;
  p1score3 = 103;
  */

  p1avgScore = (p1score1 + p1score2 + p1score3)/3;

  console.log(" Congratulations " + player1 + ". Your scores are: " + 
  p1score1 + ", " + p1score2 + ", " + p1score3 + ".");
  console.log(" Your average score of all three games are: " + 
  p1avgScore);

Answer 1

这是因为prompt()函数returns a string而不是导致(p1score1 + p1score2 + p1score3)产生字符串p1score1，p1score2和{{ 1}}，而不是对所有要素进行关节置换（即加法）。

请考虑进行以下调整并添加p1score3来解决此问题：

parseFloat()

这样做，将每个p1score1 = parseFloat( prompt(' Enter first score. ') ); p1score2 = parseFloat( prompt(' Enter second score. ') ); p1score3 = parseFloat( prompt(' Enter third score. ') );的结果解析为一个数字，这意味着prompt()等的值类型为p1score1。现在，这意味着将在此行执行加法操作，而不是字符串连接：

number

希望有帮助！

(p1score1 + p1score2 + p1score3)/3

Answer 2

您只需要将输入解析为整数/浮点数即可。

player1 = prompt(" Welcome Player 1! Please Enter your name ");
  alert(" Hello, " + player1+".");


  p1score1 = parseInt(prompt(' Enter first score. '));
  p1score2 = parseInt(prompt(' Enter second score. '));
  p1score3 = parseInt(prompt(' Enter third score. '));

  /*p1score1 = 89;
  p1score2 = 120;
  p1score3 = 103;
  */

  p1avgScore = (p1score1 + p1score2 + p1score3)/3;

  console.log(" Congratulations " + player1 + ". Your scores are: " + 
  p1score1 + ", " + p1score2 + ", " + p1score3 + ".");
  console.log(" Your average score of all three games are: " + 
  p1avgScore);

我试图找到3个要求用户输入的平均分数

2 个答案: