Question

我设置了一个按钮，单击该按钮将通过获取发布数据并创建警报。但是，我首先检查以确保某些输入不为空。如果输入元素没有值，我尝试返回一个字符串，告诉我哪个输入元素值是空的。当我这样做时，会出现“ Uncaught TypeError：postData（...）。then not a function”错误。我也查看了Uncaught TypeError: $.get(...).then is not a function，但无法弄清楚。任何帮助将不胜感激。谢谢！

document.getElementById("sbmForm").onclick = function () {postData(`/projectInfo`)
    .then(result => alert(JSON.stringify(result))) // JSON-string from `response.json()` call
    .catch(error => alert(error))};



function postData(url = ``) {
    // get form data from local storage
    var data = {};
    var unqVal = document.getElementById("unq_num").innerHTML;
    unqVal = "--??**" + unqVal;

    // keys that can not be empty
    var notEmpty = ["comp_name", "compaddr_str_num", "compaddr_str_nam", "compaddr_city",
        "compaddr_state", "compaddr_zipcode", "proj_name", "projaddr_str_num", "projaddr_str_nam",
        "projaddr_city", "projaddr_state", "projaddr_zipcode", "contact_fname", "contact_date"];
    /* get all keys and values from local storage and store them in dict to send to server */
    var keys = Object.keys(localStorage);

    var i;
    for (i=0; i < keys.length; i++){

        var val = localStorage.getItem(keys[i]);

        // if unq val is in string, add it to the data
        var indexOf = keys[i].indexOf(unqVal);

        if (indexOf != -1){

            var keyNU = keys[i].substring(0, indexOf);
            // if value is in array
            if (notEmpty.includes(keyNU)){
                // if value is empty
                if (!val){
                    alert(keyNU + " cannot be empty!");

                    /**** ERROR OCCURS HERE *****/
                    return keyNU + " cannot be empty!";
                }
            }

            data[keys[i]] = val;
        }

    }

    // Default options are marked with *
    return fetch(url, {
        method: "POST",
        headers: {
            "Content-Type": "application/json",
        },
        body: JSON.stringify(data), // body data type must match "Content-Type" header
    })
    .then(response => response.json()); // parses response to JSON
};

Answer 1

当检测到“错误”时，您将返回字符串值而不是promise。 then方法仅在promise上存在。

将您的function更改为async，以便默认情况下返回promise。

async function postData(url = ``){}

然后在需要更改时抛出错误（将被catch方法捕获）

/**** ERROR OCCURS HERE *****/
return keyNU + " cannot be empty!";

收件人

throw new Error(keyNU + " cannot be empty!");

最后，为您提取内容：

//fetch returns a promise, so use await
const res = await fetch(url, {
    method: "POST",
    headers: {
      "Content-Type": "application/json",
    },
    body: JSON.stringify(data), // body data type must match "Content-Type" header
});

//res.json() returns a promise, so use await
return await res.json();

未捕获的TypeError：postData（...）。then不是一个函数

1 个答案: