Question

我有几个句子，其中包括人名（或只是姓氏）和字符串的其余部分。我试图将他们分开作为人的名字和其余的名字。（句子总是以名字开头）

$string = "John Doe loves to eat apples";

$string = "John loves likes to run";

$string = "John Mike Doe loves to swim";

$string = "Greg McDermott lives in Sydney"; // this from comments is a good scenario.

我的数组结果应该是

[ "John Doe", 'loves to eat apples" ]
[ "John", 'likes to run" ]
[ "John Mike Doe", 'loves to swim" ]

我用preg_match_all()取得了一些成就，但是我想知道是否有更直接的方法来实现它。

$string = "John Doe loves to eat apples";
preg_match_all('/((?:^|[A-Z])[a-z]+)/', $string, $matches);
$person = implode(' ', $matches[0]);
$rest = str_replace("$person ", '', $string);

Answer 1

您可以使用此正则表达式捕获字符串开头的名称，该名称的标识是每个名字或姓氏均以大写字母开头。

^[A-Z][A-Za-z]+\b(?: \b[A-Z][A-Za-z]+\b)*

说明：

^-字符串的开头
\b[A-Z][A-Za-z]+\b-捕获名称，该名称应以大写字母开头。 \b确保不进行部分匹配。
(?: \b[A-Z][A-Za-z]+\b)*-这可以容纳名字零次或多次出现的其他姓氏。

Demo

将字符串分为ucword和小写的2个数组

1 个答案: