Question

当http请求如下所示时，我可以触摸我的代码：

private async Task OnReadyAsync()
{
    // attempt to get the channel
    var channel = _client.GetChannel(_channelId);
    // pattern match to SocketMessageChannel, the standard type required for a channel to be a messageable one
    if (!(channel is ISocketMessageChannel msgChannel)) return;

    // await the GetMessageAsync task to get the result of this task
    var msg = await msgChannel.GetMessageAsync(_msgId);
    // print Content if msg exists
    if (msg != null) Console.WriteLine(msg.Content);
}

http请求看起来像这样：

POST /init HTTP/1.1  
Host: 127.0.0.1  
Connection: keep-alive  
Content-Length: 1343

我的node.js代码是：

POST init HTTP/1.1 // what different is : the path without a '/'  
Host: 127.0.0.1  
Connection: keep-alive  
Content-Length: 1343

很遗憾，我无法更改发出http.createServer(function (req, res) { console.log('sth') }).listen(3000);请求的代码。

Answer 1

请参见以下问题：Do HTTP paths have to start with a slash?

显然，是的，要使它成为有效的HTTP请求，必须使用开始斜杠。

由于这在技术上是无效的HTTP，因此大多数库都不支持它。

Apache似乎可以容忍路径而不用斜线...也许可以将其用作反向代理吗？

另一种可能性是派生HTTP服务器库并对其进行修改以允许路径不加斜线...您可能要看一下这篇文章：https://softwareengineering.stackexchange.com/questions/349656/implement-a-http-server-on-top-of-nodejs-tcp-apis-for-learning-purposes

我如何在http模块中侦听没有'/'的路径

1 个答案: