我有一个数据库结构，其中有4个表，假设是
Table1，Table2，Table3和Table4
表1,2,3之间的关系如下：
{
"items": [
{
"componentType": "NameBox",
"lable": "name",
"properties": {
"type": "string",
"minLength": 3,
"desicription": "Enter Your Name"
}
},
{
"componenetType": "UserNameBox",
"lable": "username",
"properties": {
"type": "string",
"minLength": 4,
"maxLength": 8,
"description": "Enter user name"
}
},
{
"componenetType": "EmailBox",
"lable": "email",
"properties": {
"type": "string",
"pattern": "^[a-z0-9]+(\\.[_a-z0-9]+)*@[a-z0-9-]+(\\.[a-z0-9-]+)*(\\.[a-z]{2,15})$",
"description": "Enter email"
}
},
{
"componenetType": "PasswordBox",
"lable": "password",
"properties": {
"type": "string",
"pattern": "^(?=.*[0-9])(?=.*[!@#$%^&*])[a-zA-Z0-9!@#$%^&*]{6,16}$",
"description": "Enter password"
}
},
{
"componentType": "CountryDropDown",
"lable": "country",
"properties": {
"type": "string",
"enum": [
"AUS",
"IN",
"JP",
"US",
"RU",
"Other"
]
}
},
{
"componenetType": "RadioButton",
"lable": "gender",
"properties": {
"type": "string",
"anyOf": [
{
"type": "radios",
"key": "radios",
"enum": [
{
"value": "male",
"name": "Male"
},
{
"value": "female",
"name": "Female"
}
]
}
]
}
},
{
"componenetType": "CheckBox",
"lable": "language",
"properties": {
"type": "array",
"items": {
"type": "string",
"enum": [
"english",
"spanish",
"japanese",
"french",
"hindi"
]
}
}
},
{
"componenetType": "SubmitButton",
"lable": "Submit",
"properties": {
"type": "submit",
"title": "Submit"
}
}
]
}
现在有另一个表Table4，它具有一个键引用，该键引用是table1，table2，table3的外键，即该表看起来像这样
(Table1).hasMany(Table2)
(Table2).hasMany(Table3)
如何定义表之间的关系。在文档中没有提到这样的用例。有没有解决的办法？还是显示我在不定义外键关系的情况下存储数据？