Question

我想创建一个托管的Compute Engine组，其中包含一些启动脚本，其中包括一个创建对象更改通知的订阅的脚本。在these tutorials之后，这些订阅都需要一个“ subscription_name”。

我无法将其设置为静态名称，因为当启动1个以上的VM时，它将导致冲突。

是否可以自动“递增”名称，即“ VM_sub_1”，“ VM_sub_2”，“ VM_sub_3” ...等？

还是将其保留为空白并接受随机生成的名称是避免冲突的唯一方法？

用于创建订阅的代码示例：

def create_push_subscription(project_id, topic_name, subscription_name, endpoint):
"""Create a new push subscription on the given topic."""
# [START pubsub_create_push_subscription]
from google.cloud
import pubsub_v1
project_id = "bucketcfpubsub"
topic_name = "bucketcfpubsub"
subscription_name = "VM_sub_1"
endpoint = "https://bucketcfpubsub.appspot.com/push"
subscriber = pubsub_v1.SubscriberClient()
topic_path = subscriber.topic_path(project_id, topic_name)
subscription_path = subscriber.subscription_path(project_id, subscription_name)

push_config = pubsub_v1.types.PushConfig(push_endpoint = endpoint)
subscription = subscriber.create_subscription(subscription_path, topic_path, push_config)
print('Push subscription created: {}'.format(subscription))
print('Endpoint for subscription is: {}'.format(endpoint))#[END pubsub_create_push_subscription]

尝试获取元数据：

def check_instance():
    import time
    import requests

    METADATA_URL = 'http://metadata.google.internal/computeMetadata/v1/instance/id'
    METADATA_HEADERS = {'Metadata-Flavor': 'Google'}

    instance_id = requests.get(METADATA_URL, headers=METADATA_HEADERS)

    print(instance_id)

check_instance()

返回

响应[200]

意味

成功！值已更改，或者您达到了指定的timeout_sec，请求成功返回。

多个虚拟机的Google PubSub订阅名称？

0 个答案: