我在Windows 10上运行jq v1.6，
我的输入是“ 2009-12-20 08:00:00”，我想获取星期几。
我的测试过滤器是("2009-12-20 08:00:00" | sub(" "; "T") + "Z" | fromdate | gmtime)
但我得到的只是一个错误：
jq：错误：该平台未实现strptime / 1
尝试了很多东西，但没有任何效果。
builtins返回相关功能：
[ "input_line_number/0", "input_filename/0", "now/0", "localtime/0", "gmtime/0", "mktime/0", "strflocaltime/1", "strftime/1", "strptime/1", "stderr/0", "debug/0", "modulemeta/0", "get_jq_origin/0", "get_prog_origin/0", "get_search_list/0", "halt_error/1", "halt/0", "env/0", "format/1", "error/1", "max/0", "min/0", "sort/0", "nan/0", "infinite/0", "isnormal/0", "isnan/0", "isinfinite/0", "type/0", "utf8bytelength/0", "length/0", "contains/1", "has/1", "delpaths/1", "getpath/1", "setpath/2", "implode/0", "explode/0", "split/1", "rtrimstr/1", "ltrimstr/1", "endswith/1", "startswith/1", "keys_unsorted/0", "keys/0", "tostring/0", "tonumber/0", "fromjson/0", "tojson/0", "modf/0", "frexp/0", "ldexp/2", "trunc/0", "scalbln/2", "round/0", "rint/0", "nexttoward/2", "nextafter/2", "nearbyint/0", "logb/0", "log1p/0", "lgamma/0", "fmod/2", "fmin/2", "fmax/2", "fma/3", "fdim/2", "fabs/0", "expm1/0", "erfc/0", "erf/0", "copysign/2", "ceil/0", "yn/2", "jn/2", "y1/0", "y0/0", "tgamma/0", "tanh/0", "tan/0", "sqrt/0", "sinh/0", "sin/0", "remainder/2", "pow/2", "log2/0", "log10/0", "log/0", "j1/0", "j0/0", "hypot/2", "floor/0", "exp2/0", "exp/0", "cosh/0", "cos/0", "cbrt/0", "atanh/0", "atan2/2", "atan/0", "asinh/0", "asin/0", "acosh/0", "acos/0", "empty/0", "not/0", "path/1", "range/2", "halt_error/0", "error/0", "map/1", "select/1", "sort_by/1", "group_by/1", "unique/0", "unique_by/1", "max_by/1", "min_by/1", "add/0", "del/1", "map_values/1", "recurse/1", "recurse/2", "recurse/0", "recurse_down/0", "to_entries/0", "from_entries/0", "with_entries/1", "reverse/0", "indices/1", "index/1", "rindex/1", "paths/0", "paths/1", "any/2", "any/1", "any/0", "all/2", "all/1", "all/0", "isfinite/0", "arrays/0", "objects/0", "iterables/0", "booleans/0", "numbers/0", "normals/0", "finites/0", "strings/0", "nulls/0", "values/0", "scalars/0", "scalars_or_empty/0", "leaf_paths/0", "join/1", "flatten/1", "flatten/0", "range/1", "fromdateiso8601/0", "todateiso8601/0", "fromdate/0", "todate/0", "match/2", "match/1", "test/2", "test/1", "capture/2", "capture/1", "scan/1", "splits/2", "splits/1", "split/2", "sub/2", "sub/3", "gsub/3", "gsub/2", "range/3", "while/2", "until/2", "limit/2", "isempty/1", "first/1", "last/1", "nth/2", "first/0", "last/0", "nth/1", "combinations/0", "combinations/1", "transpose/0", "in/1", "inside/1", "input/0", "repeat/1", "inputs/0", "ascii_downcase/0", "ascii_upcase/0", "truncate_stream/1", "fromstream/1", "tostream/0", "bsearch/1", "walk/1", "INDEX/2", "INDEX/1", "JOIN/2", "JOIN/3", "JOIN/4", "IN/1", "IN/2", "drem/2", "exp10/0", "gamma/0", "pow10/0", "scalb/2", "significand/0", "lgamma_r/0", "builtins/0" ]
答案 0 :(得分：1)
以下是在Windows 10计算机上解决问题的两种替代方法：
然后，一旦安装了jq（例如，使用linuxbrew），则可以使用以下过滤器：
"2009-12-20 08:00:00"
| strptime("%Y-%m-%d %T")
| strftime("%a")
它会产生“ Sun”（这是正确的：-）
# Use Zeller's Congruence to determine the day of the week, given
# year, month and day as integers in the conventional way.
# Emit 0 for Saturday, 1 for Sunday, etc.
#
def day_of_week($year; $month; $day):
if $month == 1 or $month == 2 then
[$month + 12, $year - 1]
else
[$month, $year]
end
| $day + (13*(.[0] + 1)/5|floor)
+ (.[1]%100) + ((.[1]%100)/4|floor)
+ (.[1]/400|floor) - 2*(.[1]/100|floor)
| . % 7 ;
"2009-12-20 08:00:00"
| capture("(?<Y>\\d+)-(?<m>\\d+)-(?<d>\\d+)")
| map_values(tonumber)
| day_of_week(.Y; .m; .d)
这将产生1，表示星期日。