Question

所以我需要做的是计算周一至周五从0900到1600的租赁时间并存储

我已经尝试删除一天的计算，但是仍然无法以正确的格式进行编译。

public class Time {

    // Variables

    static Scanner kbinput = new Scanner(System.in);

    private static boolean error = false;

    private static String daysoftheweek;            //  Monday, Tuesday, Wednesday, Thursday, Friday, Saturday, Sunday;

    DateFormat sdf = new SimpleDateFormat("HH");
    // Keyboard for user input

    private int time;

    public static void main(String[] args) throws ParseException {

        System.out.println("Please enter day of your rental");
        daysoftheweek = kbinput.nextLine();
        System.out.println("Please enter day of your return");

        do {
            daysoftheweek = kbinput.nextLine();
            switch (daysoftheweek.toUpperCase()) {
                case "Monday":
                    error = false;
                    break;
                case "Tuesday":
                    error = false;
                    break;
                case "Wednesday":
                    error = false;
                    break;
                case "Thursday":
                    error = false;
                    break;
                case "Friday":
                    break;
                case "Saturday":
                default:
                case "Sunday":
            }

        } while (error);

        System.out.println("Please enter your start time (hh) ");

        String time = kbinput.nextLine();

        System.out.println();
        System.out.print("Enter finish time (hh) ");

        String time2 = kbinput.nextLine();

        DateFormat sdf = new SimpleDateFormat("hh");

        Date d1 = sdf.parse(time);
        System.out.println("Rental Time: " + sdf.format(d1));
    }
}

Answer 1

Java中的字符串比较区分大小写。在该行中：

switch (daysoftheweek.toUpperCase()) {

您将用户的输入转换为全部大写的字符串，即“星期一”变为“星期一”。这永远不会匹配switch块中的任何情况。

一个短期解决方案是将所有案例替换为其大写版本。一种更可靠的方法是在一周中的几天内使用内置的Java enumeration。

如何以小时为单位计算时间并使周末返回无效消息

1 个答案: