Question

如果元组的第一个值与另一个元组重复，则需要从元组列表中删除该元组。例如，这是一个元组列表

 ('Auckland', 23, 'https://en.wikipedia.org/wiki/Auckland'),
 ('genera', 23, 'https://en.wikipedia.org/wiki/Genus'),
 ('Auckland', 23, 'https://en.wikipedia.org/wiki/Auckland_Airport'),
 ('Auckland', 23, 'https://en.wikipedia.org/wiki/Auckland'),
 ('Auckland', 23, 'https://en.wikipedia.org/wiki/Auckland'),
 ('Auckland', 23, 'https://en.wikipedia.org/wiki/Auckland'),
 ('Auckland', 23, 'https://en.wikipedia.org/wiki/Auckland_Region'),
 ('Auckland', 23, 'https://en.wikipedia.org/wiki/Auckland_Region'),
 ('Auckland', 23, 'https://en.wikipedia.org/wiki/Auckland'),
 ('Islands',28,'https://en.wikipedia.org dddfdfdf/wiki/'),
 ('South Island', 29, 'https://en.wikipedia.org/wiki/South_Island'),
 ('South Island', 29, 'https://en.wikipedia.org/wiki/South_Island'),
 ('South Island', 29, 'https://en.wikipedia.org/wiki/South_Island'),
 ('South Island', 29, 'https://en.wikipedia.org/wiki/South_Island'),

输出必须是这样的：

 ('Auckland', 23, 'https://en.wikipedia.org/wiki/Auckland'),
 ('genera', 23, 'https://en.wikipedia.org/wiki/Genus'),
 ('Islands',28,'https://en.wikipedia.org dddfdfdf/wiki/'),
 ('South Island', 29, 'https://en.wikipedia.org/wiki/South_Island')

我正在尝试一切在网络上进行搜索

Answer 1

您好，欢迎来到Stack Overflow。您的问题提到了元组的列表。因此，我假设您的列表如下所示：

all =[('Auckland', 23, 'https://en.wikipedia.org/wiki/Auckland'),
('genera', 23, 'https://en.wikipedia.org/wiki/Genus'),
('Auckland', 23, 'https://en.wikipedia.org/wiki/Auckland_Airport'),
('Auckland', 23, 'https://en.wikipedia.org/wiki/Auckland'),
('Auckland', 23, 'https://en.wikipedia.org/wiki/Auckland'),
('Auckland', 23, 'https://en.wikipedia.org/wiki/Auckland'),
('Auckland', 23, 'https://en.wikipedia.org/wiki/Auckland_Region'),
('Auckland', 23, 'https://en.wikipedia.org/wiki/Auckland_Region'),
('Auckland', 23, 'https://en.wikipedia.org/wiki/Auckland'),
('Islands',28,'https://en.wikipedia.org dddfdfdf/wiki/'),
('South Island', 29, 'https://en.wikipedia.org/wiki/South_Island'),
('South Island', 29, 'https://en.wikipedia.org/wiki/South_Island'),
('South Island', 29, 'https://en.wikipedia.org/wiki/South_Island'),
('South Island', 29, 'https://en.wikipedia.org/wiki/South_Island')]

在这种情况下，基于第一个值获得唯一结果的最简单方法是将元组列表更改为一组（始终唯一，并在以下for循环中保存许多不必要的迭代），然后循环执行此操作方式：

unique_all = list(set(all))
first_values = []
for t in unique_all:
    if t[0] in first_values:
        unique_all.remove(t)
    else:
        first_values.append(t[0])

print(unique_all)

输出将是：

[('Auckland', 23, 'https://en.wikipedia.org/wiki/Auckland_Airport'),
 ('South Island', 29, 'https://en.wikipedia.org/wiki/South_Island'),
 ('genera', 23, 'https://en.wikipedia.org/wiki/Genus'),
 ('Islands', 28, 'https://en.wikipedia.org dddfdfdf/wiki/')]

我想这就是你的问题。

Answer 2

只要遇到唯一元组[0]，您就可以遍历列表并将元组添加到新列表中。

l = [your list from above]    
uniques = set()
new_l = []
for tup in l:
    if tup[0] not in uniques:
        new_l.append(tup)
        uniques.add(tup[0])
print(new_l)

输出：

[('Auckland', 23, 'https://en.wikipedia.org/wiki/Auckland'), 
('genera', 23, 'https://en.wikipedia.org/wiki/Genus'), 
('Islands', 28, 'https://en.wikipedia.org dddfdfdf/wiki/'), 
('South Island', 29, 'https://en.wikipedia.org/wiki/South_Island')]

如果您真的想删除，列表可能不是保存它的最佳数据结构，因为从列表中间删除是O（n）操作，而不是从结尾删除或追加是O （1）。

Answer 3

将所有这些都放在列表中。

     l = [('Auckland', 23, 'https://en.wikipedia.org/wiki/Auckland'),
     ('genera', 23, 'https://en.wikipedia.org/wiki/Genus'),
     ('Auckland', 23, 'https://en.wikipedia.org/wiki/Auckland_Airport')]

...

现在输入：

k = []
m = []
for i in l :
    if i[0] in k :
        pass 
    else :
        k.append([i[0]])
        m.append(i)
    print(m)

如果元组的第一个值是另一个元组的重复项，则如何从元组列表中删除元组

3 个答案: