如何选择仅显示不相等的数据结果，而只显示负数或盲目的相等数据结果？

Question

这是我的机器人代码

两个表上都有22条记录，但是只有1条记录具有不相等的数据，我想显示该结果，并减去或盲目相等的数据结果。

 connect to database using custom params  cx_Oracle    ${DB_CONNECT_STRING}
 @{queryResultsA}=   Query  Select count (*) from QA_USER.SealTest_Security_A order by SECURITY_ID
 Log  ${queryResultsA}
 @{queryResultsB}=   Query  Select count (*) from QA_USER.SealTest_Security_B order by SECURITY_ID
 Log  ${queryResultsB}

should not contain match    ${queryResultsB}  ${queryResultsA}

Answer 1

1. 使用循环

    # Assuming your table has values like this
   @{queryResultsA}=   Create List     a   b   c   d   e
   @{queryResultsB}=   Create List     a   z   c   d   e
   
   ${Length}=  Get Length      ${queryResultsA}
   ${count}=   Set Variable
   
   :FOR     ${count}   IN RANGE     ${Length}      
   \       Run Keyword If  '@{queryResultsA}[${count}]'!='@{queryResultsB}[${count}]'      Log To Console      @{queryResultsA}[${count}] @{queryResultsB}[${count}]
   

   输出
   b z

2. 使用SET

   ${z} =  Evaluate    (set(${queryResultsA}) - set(${queryResultsB}))
   Log     ${z}
   

   输出
   b

   请注意，这里从集合A中减去了集合B的差异，所以在集合A中不匹配的内容将作为输出。