Question

我希望通过删除重复项而不分配给第三个变量来连接两个数组：

var arr1=[{id:1,name:'AB'},{id:2,name:'CD'}];

var arr2=[{id:3,name:'EF'},{id:2,name:'CD'}];

我想要arr1：

[{id:1,name:'AB'},{id:2,name:'CD'},{id:3,name:'EF'}]

arr1.concat(arr2);

Answer 1

首先合并两个数组，然后将其ID放入数组中。然后根据地图值创建数组。

var arr1=[{id:1,name:'AB'},{id:2,name:'CD'}];
var arr2=[{id:3,name:'EF'},{id:2,name:'CD'}];

arr1 = arr1.concat(arr2) // merge two arrays
let foo = new Map();
for(const tag of arr1) {
  foo.set(tag.id, tag);
}
let final = [...foo.values()]
console.log(final)

Answer 2

可以使用数组reduce和findIndex来实现所需的功能。

var arr1=[{id:1,name:'AB'},{id:2,name:'CD'}];

var arr2=[{id:3,name:'EF'},{id:2,name:'CD'}];

// loop over arr2, add the elements of array2 if it doesn't exist in array1
var newArr = arr2.reduce((acc, eachArr2Elem) => {
  if (arr1.findIndex((eachArr1Elem) => eachArr1Elem.id === eachArr2Elem.id && eachArr1Elem.name === eachArr2Elem.name)  === -1) {
    acc.push(eachArr2Elem)
  }
  return acc
}, [...arr1]); // initialize the new Array with the contents of array1

console.log(newArr)

Answer 3

通过使用lodash _.uniqWith(array, [comparator])

var objects = [{ 'x': 1, 'y': 2 }, { 'x': 2, 'y': 1 }, { 'x': 1, 'y': 2 }];

_.uniqWith(objects, _.isEqual);
// => [{ 'x': 1, 'y': 2 }, { 'x': 2, 'y': 1 }]

Answer 4

使用public function Functionname(Request $request, $id, $username, $bio)运算符，您可以展平传递给spread方法的任意数量的数组，我还为（希望）更具可读性的代码拆分了一些逻辑方法。我希望这会有所帮助。

combineAndDeDup

Answer 5

<!everyone>

数据变量包含您的唯一数组

如何合并两个数组并删除JavaScript中的重复项

5 个答案: