我必须在程序中应用if else条件。我是python GUI的新手,无法弄清楚if语句如何放入程序中。
如果else语句如下:
if(weight>50 and glue==1):
print("Tear in Seat")
elif(weight<50 and glue==0):
print("No Tear in Seat")
elif(weight>70 and glue==0):
print("Tear in Seat")
elif(weight<70 and glue==1):
print("No tear in Seat")
这是我的GUI表单:
from tkinter import *
fields = 'Weight Applied', 'Glue 0 || 1'
def fetch(entries, weight, glue):
for entry in entries:
field = entry[0]
text = entry[1].get()
print('%s: "%s"' % (field, text))
if weight > 50 and glue == 1:
print("Tear in Seat")
elif weight < 50 and glue == 0:
print("No Tear in Seat")
elif weight > 70 and glue == 0:
print("Tear in Seat")
elif weight < 70 and glue == 1:
print("No tear in Seat")
def makeform(root, fields):
entries = []
for field in fields:
row = Frame(root)
lab = Label(row, width=15, text=field, anchor='w')
ent = Entry(row)
row.pack(side=TOP, fill=X, padx=5, pady=5)
lab.pack(side=LEFT)
ent.pack(side=RIGHT, expand=YES, fill=X)
entries.append((field, ent))
return entries
if __name__ == '__main__':
root = Tk()
ents = makeform(root, fields)
root.bind('<Return>', (lambda event, e=ents: fetch(e)))
b1 = Button(root, text='Show', command=(lambda e=ents: fetch(e)))
b1.pack(side=LEFT, padx=5, pady=5)
b2 = Button(root, text='Quit', command=root.quit)
b2.pack(side=LEFT, padx=5, pady=5)
root.mainloop()
答案 0 :(得分:1)
根据您的代码逻辑,应将if-else
块放在fetch(...)
函数中,如下所示:
def fetch(entries):
weight = glue = 0
for entry in entries:
field = entry[0]
text = entry[1].get()
if 'Weight' in field:
weight = int(text)
elif 'Glue' in field:
glue = int(text)
print("weight:", weight, ", glue:", glue)
if weight > 50 and glue == 1:
print("Tear in Seat")
elif weight < 50 and glue == 0:
print("No Tear in Seat")
elif weight > 70 and glue == 0:
print("Tear in Seat")
elif weight < 70 and glue == 1:
print("No tear in Seat")
else:
print("Invalid weight and glue")