Question

我有一列包含这样的字符串：

Traceback (most recent call last):
  File "hello.py", line 11, in <module>
    founders = soup.select('.founders section .section with_filler 
with_editable_regions dsss17 startups-show-sections ffs70 founders _a _jm 
.dsr31 startup_roles fsp87 startup_profile_group _a _jm .larger roles 
role')
  File "C:\Users\nandi\Anaconda3\lib\site-packages\bs4\element.py", line 
1477, in select
    'Unsupported or invalid CSS selector: "%s"' % token)
ValueError: Unsupported or invalid CSS selector: "_a"

和我使用的查询：

+-------------------+
|       type        |
+-------------------+
|cashback_percentage|
|   cashback_fix    |
|        fix        |
+-------------------+

但是我得到了这样的结果：

SELECT CONCAT(UCASE(LEFT(replace(type, " ", "_"), 1))) as new_type from mytable;

我希望结果删除下划线并将其替换为空格，并在每个单词上将每个首字母大写，如下所示：

+-------------------+
|      new_type     |
+-------------------+
|         C         |
|         C         |
|         F         |
+-------------------+

Answer 1

您在正确的轨道上。这种方法是先进行串联，对第一个字母进行大写，然后对整个字符串进行替换，以将下划线与空格交换。

SELECT
    type,
    REPLACE(CONCAT(UPPER(LEFT(type, 1)), SUBSTRING(type, 2)), '_', ' ') AS output
FROM yourTable;

Demo

Answer 2

您可以使用Replace

select replace(type, '_', ' ') from tb

要大写，您可以使用自定义功能

CREATE FUNCTION CAP_FIRST (input VARCHAR(255))   
RETURNS VARCHAR(255)  
DETERMINISTIC    
BEGIN
    DECLARE len INT;
    DECLARE i INT;

    SET len   = CHAR_LENGTH(input);
    SET input = LOWER(input);
    SET i = 0;

    WHILE (i < len) DO
        IF (MID(input,i,1) = ' ' OR i = 0) THEN
            IF (i < len) THEN
                SET input = CONCAT(
                    LEFT(input,i),
                    UPPER(MID(input,i + 1,1)),
                    RIGHT(input,len - i - 1)
                );
            END IF;
        END IF;
        SET i = i + 1;
    END WHILE;

    RETURN input;
END;

用法

select CAP_FIRST(replace(type, '_', ' ')) from tb

Working Fiddler

替换Undercase和Capitlize MySQL中的第一个字母

2 个答案:

Demo