如何解决“未报告的异常AWTException;必须被捕获或声明为抛出”。机器人实例

时间:2019-01-08 02:32:37

标签: java instance instanceof awtrobot

实例化一个类,该类包含使用Robot进行鼠标和键移动的方法时,出现错误“未报告的异常AWTException;必须被捕获或声明为抛出”。我尝试了try catch在该实例中,但“点击”无法通过这种方式工作,请问如何解决呢?

package Ventanas;

    enter code here

import java.awt.AWTException;
import java.awt.Robot;
import java.awt.event.InputEvent;

public class Sel {

    Robot robot = new Robot();

    public void apos() throws AWTException {

        //mouseMv(1408, 1001);  
        //leftClick(); 
        mouseMv(1383, 216);
        leftClick();
        //mouseMv(1408, 1001);
        //leftClick(); 
    }

    public Sel() throws AWTException {

        robot.setAutoDelay(40);
        robot.setAutoWaitForIdle(true);
    }

    public void leftClick() throws AWTException {

        robot.mousePress(InputEvent.BUTTON1_MASK);
        robot.delay(200);
        robot.mouseRelease(InputEvent.BUTTON1_MASK);
        robot.delay(200);
    }

    public void mouseMv(int x, int y) throws AWTException {

        robot.mouseMove(x, y);
    }

    public void abrirFavoritos() throws AWTException {
        //1408 999
        try {
            mouseMv(1408, 999);
            leftClick();
        } catch (NullPointerException e) {
            System.out.println(e);
        }

    }

}

-----------------------------------------------------------------------

//Another class
    private void IniciarActionPerformed(java.awt.event.ActionEvent evt) {                                        

            Metodos a = new Metodos();

            Sel s = new Sel(); //Here is the error
    }

1 个答案:

答案 0 :(得分:1)

通过使用try-catch之类的

try {
    Sel s = new Sel();
    // ...
} catch (AWTException ae) {
    ae.printStackTrace();
}

或修改此方法的签名以引发异常。也就是说,改变

private void IniciarActionPerformed(java.awt.event.ActionEvent evt)

private void IniciarActionPerformed(java.awt.event.ActionEvent evt) throws AWTException