Question

我有一个CTE表，没有。计算的工作日数，以及一个单独的查询，我希望将此CTE表联接并在wkdaysinmonth，wkdaystodate中读取，但是我有点迷失了如何将这两个联接在一起并获得结果：

 with dates as(
        select dateadd(d,-day(getdate())+1,convert(date,getdate())) as startofmonth,
        dateadd(d,-1,dateadd(m,1,dateadd(d,-day(getdate())+1,convert(date,getdate())))) as endofmonth,
        convert(date,getdate()) as today
    ), holidays as (
        select *
        from (values ('20181224'),('20181225'),('20181231')) x (holiday)
     )
    ,holidaycount as (
        select count(*) as holidaysinmonth,
            sum(case when holiday<=today then 1 else 0 end) as holidaystodate
        from dates
        join holidays on holiday between startofmonth and endofmonth
    )
    ,daycounts as(
        select dates.*,

           (DATEDIFF(dd, startofmonth, endofmonth) + 1)
          -(DATEDIFF(wk, startofmonth, endofmonth) * 2)
          -(CASE WHEN DATENAME(dw, startofmonth) = 'Sunday' THEN 1 ELSE 0 END) 
          -(CASE WHEN DATENAME(dw, endofmonth) = 'Saturday' THEN 1 ELSE 0 END)
          -isnull(holidaysinmonth,0) as wkdaysinmonth,

           (DATEDIFF(dd, startofmonth, today) + 1)
          -(DATEDIFF(wk, startofmonth, today) * 2)
          -(CASE WHEN DATENAME(dw, startofmonth) = 'Sunday' THEN 1 ELSE 0 END) 
          -(CASE WHEN DATENAME(dw, today) = 'Saturday' THEN 1 ELSE 0 END)
          -isnull(holidaystodate,0) as wkdaystodate

        from dates
        cross join holidaycount
    )

-------------代码2 -------------

select i.inv_date, c.SALES_ID, s.CL_KEY,
    sum(i.MERCH - i.COGS) as GP
from invoice i 
left join vw_MomOrdDetail c on c.orderno = i.ORDERNO and c.INPART = i.INPART
left join CMS s on s.ORDERNO = i.ORDERNO
where i.INV_DATE = '2019-01-02 00:00:00.000'
group by i.INV_DATE, CL_KEY, c.SALES_ID

我尝试了类似的方法，但是没有用：

with dates as(
    select dateadd(d,-day(getdate())+1,convert(date,getdate())) as startofmonth,
    dateadd(d,-1,dateadd(m,1,dateadd(d,-day(getdate())+1,convert(date,getdate())))) as endofmonth,
    convert(date,getdate()) as today
), holidays as (
    select *
    from (values ('20181224'),('20181225'),('20181231')) x (holiday)
 )
,holidaycount as (
    select count(*) as holidaysinmonth,
        sum(case when holiday<=today then 1 else 0 end) as holidaystodate
    from dates
    join holidays on holiday between startofmonth and endofmonth
)
,daycounts as(
    select dates.*,

       (DATEDIFF(dd, startofmonth, endofmonth) + 1)
      -(DATEDIFF(wk, startofmonth, endofmonth) * 2)
      -(CASE WHEN DATENAME(dw, startofmonth) = 'Sunday' THEN 1 ELSE 0 END) 
      -(CASE WHEN DATENAME(dw, endofmonth) = 'Saturday' THEN 1 ELSE 0 END)
      -isnull(holidaysinmonth,0) as wkdaysinmonth,

       (DATEDIFF(dd, startofmonth, today) + 1)
      -(DATEDIFF(wk, startofmonth, today) * 2)
      -(CASE WHEN DATENAME(dw, startofmonth) = 'Sunday' THEN 1 ELSE 0 END) 
      -(CASE WHEN DATENAME(dw, today) = 'Saturday' THEN 1 ELSE 0 END)
      -isnull(holidaystodate,0) as wkdaystodate

    from dates
    cross join holidaycount
)
SELECT o1.inv_date,o1.SALES_ID,o1.CL_KEY,o1.weekdaysinmonth
FROM
(select i.inv_date, c.SALES_ID, s.CL_KEY,
(select wkdaysinmonth from daycounts) as weekdaysinmonth,
(select wkdaystodate from daycounts) as weekdaystodate,
    sum(i.MERCH - i.COGS) as GP
from invoice i 
left join vw_MomOrdDetail c on c.orderno = i.ORDERNO and c.INPART = i.INPART
left join CMS s on s.ORDERNO = i.ORDERNO
where i.INV_DATE = '2019-01-02 00:00:00.000'
group by i.INV_DATE, CL_KEY, c.SALES_ID) AS o1 on o1.SALES_ID=c.SALES_ID

错误：关键字“ on”附近的语法不正确。

所需的输出列为：

inv_date,SALES_ID,CL_KEY,weekdaysinmonth

感谢您的帮助。谢谢

Answer 1

错误消息说

关键字“ on”附近的语法不正确

因为您的联接引用了在括号生成表o1中声明的表别名

我建议您创建一个calendar table，而不是动态生成日期。您可以有假期字段，wkdaysinmonth和wkdaystodate可以预先计算，并且只有一个表要联接。

关于您的代码样式的注释；您应该在代码中坚持一种大写形式，这使查询更易于阅读。有时您将ALL_CAPS用于表名和字段名，而有时all_lower则交替使用。

我在SQL Server上看到的常见样式是：

Capitalised_Table_Names.all_lower_field_names

即使您不喜欢该样式，也请定义自己的样式，但要保持一致。

Answer 2

发生错误的原因是您试图在“外部”查询中引用“内部”表。您只能做相反的事情。您也有一个ON，而没有JOIN。

简而言之，您拥有的是：

SELECT ... FROM (Derived Table) o1 ON o1.Column=c.Column

不仅该ON子句没有JOIN，而且外部查询中不存在别名c。

您需要将c与派生表本身而不是外部查询中的其他表进行所有关联。

通过查询加入CTE（工作日数）

2 个答案: