使用PDO将数组值作为对象属性

时间:2019-01-07 22:35:52

标签: php oop mysqli pdo properties

我想将数组值存储为对象属性。我正在以mysqli为例,但我想改用PDO。

我有一个用户类别:

class User {

public $id;
public $username;
public $password;
public $first_name;
public $last_name;

public static function find_all_users(){
    global $database;
    $result_set = $database->query($sql);
    return $result_set;
  } //end method
} //end User class

我已使用以下数据库类连接到我的数据库。 注意:常数DB_SERVER等已在其他位置定义并包含在文件中

class Database{

public $connection;

function __construct(){
    $this->open_db_connection();
}//end of constructor

public function open_db_connection(){
   try{
      $this->connection = new PDO('mysql:host='. DB_SERVER .';dbname='. DB_NAME, DB_USER, DB_PASSWORD);
      $this->connection->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
   }catch(PDOException $e){
      echo 'Server Error: ' . $e->getCode(;
   }//end catch block
}//end of method    

public function query($sql){
    $stmt = $this->connection->prepare($sql);
    $stmt->execute();
    $result = $stmt->fetchAll(PDO::FETCH_ASSOC);
    return $result;
} //end query method

$database = new Database();

我想从User类创建一个对象,并使用该类的属性访问我的数据。

$user = new User();
$user->id = $result_set['id'];
$user->username = $result_set['username'];
$user->password = $result_set['password'];
$user->first_name = $result_set['first_name'];
$user->last_name = $result_set['last_name'];
echo $user->id;

在mysqli中,将通过以下操作完成

public static function find_all_users(){
   global $database;
   $result_set = $database->query($sql);
   mysqli_fetch_array($result_set);
   return $result_set;
   } //end method

我得到的错误是 “未定义的索引:ID” “未定义的索引:用户名” “未定义的索引:密码” “未定义的索引:first_name” “未定义的索引:last_name”

我认为我的错误来自fetchAll(PDO :: FETCH_ASSOC)。我应该从echo语句中获取一个值。回声$ user-> id;

有什么更好的获取方法与PDO的mysqli_fetch_array相似?

下面是当我print_r $ result_set时:

print_r of $result_set

1 个答案:

答案 0 :(得分:-1)

fetchAll()返回一个二维数组。您需要遍历元素:

$all_users = array();
foreach ($result_set as $result) {
    $user = new User();
    $user->id = $result['id'];
    $user->username = $result['username'];
    $user->password = $result['password'];
    $user->first_name = $result['first_name'];
    $user->last_name = $result['last_name'];
    $all_users[] = $user;
    echo $user->id;
}