这似乎是一个重复的问题,如果可以,请帮我,因为我读到的所有内容都没有帮助:(
这些天我一直在学习React,不要对我太苛刻,我正在React站点的tic tac toe教程的基础上进行构建,并将其扩展为4x4网格以获得更多乐趣。一切都像原始教程一样。
现在,我正在尝试通过传递将通过Square函数从Board类继承的props中的样式,来动态设置X的蓝色和O的蓝色。
它可以工作,但颜色不会从红色改变。...
任何帮助将不胜感激。
class Game extends React.Component {
constructor(props) {
super(props);
this.state = {
history: [
{
squares: Array(16).fill(null)
}
],
xTurn: true,
stepNumber: 0
};
}
/**
* goes to history state of game
* @param step - the move number
*/
jumpTo(step) {
this.setState({
stepNumber: step,
xTurn: step % 2 === 0
});
}
handleClick(i) {
const history = this.state.history.slice(0, this.state.stepNumber + 1);
const current = history[history.length - 1];
const squares = current.squares.slice();
if (calculateWinner(squares) || squares[i]) {
return;
}
squares[i] = this.state.xTurn ? 'X' : 'O';
this.setState({
history: history.concat([
{
squares: squares
}
]),
stepNumber: history.length,
xTurn: !this.state.xTurn
});
}
render() {
const history = this.state.history;
const current = history[this.state.stepNumber];
const winner = calculateWinner(current.squares);
const moves = history.map((step, move) => {
const desc = move ? 'Go to move #' + move : 'Go to start';
return (
<li key={move}>
<button onClick={() => this.jumpTo(move)}>{desc}</button>
</li>
);
});
let status;
if (winner) {
status = 'Winner: ' + winner;
} else {
status = 'Next player is ' + (this.state.xTurn ? 'X' : 'O');
}
return (
<div className="game">
<h1 className="title">JJBA 4 WAY TIC TAC TOE</h1>
<div className="game-rules">
Plays like regular game except that players can win three ways: 4
corners, 4 in a square (anywhere on the board) or 4 in a row
(vertical, horizontal, diagonal).
</div>
<br />
<div className="game-container">
<Board squares={current.squares} onClick={i => this.handleClick(i)} />
</div>
<div className="game-info">
<div>{status}</div>
<ol>{moves}</ol>
</div>
</div>
);
}
}
const xColor = { color: '#3ab3ab' };
const oColor = { color: 'red' };
class Board extends React.Component {
renderSquare(i) {
return (
<Square
value={this.props.squares[i]}
onClick={() => this.props.onClick(i)}
style={this.props.xTurn ? xColor : oColor}
/>
);
}
render() {
return (
<div className="game-board">
<div className="board-row">
{this.renderSquare(0)}
{this.renderSquare(1)}
{this.renderSquare(2)}
{this.renderSquare(3)}
</div>
<div className="board-row">
{this.renderSquare(4)}
{this.renderSquare(5)}
{this.renderSquare(6)}
{this.renderSquare(7)}
</div>
<div className="board-row">
{this.renderSquare(8)}
{this.renderSquare(9)}
{this.renderSquare(10)}
{this.renderSquare(11)}
</div>
<div className="board-row">
{this.renderSquare(12)}
{this.renderSquare(13)}
{this.renderSquare(14)}
{this.renderSquare(15)}
</div>
</div>
);
}
}
function calculateWinner(squares) {
const lines = [
[0, 1, 2, 3],
[4, 5, 6, 7],
[8, 9, 10, 11],
[12, 13, 14, 15],
[0, 4, 8, 12],
[1, 5, 9, 13],
[2, 6, 10, 14],
[3, 7, 11, 15],
[0, 5, 10, 15],
[3, 6, 9, 12],
[0, 1, 4, 5],
[1, 2, 5, 6],
[2, 3, 6, 7],
[4, 5, 8, 9],
[5, 6, 9, 10],
[6, 7, 10, 11],
[8, 9, 12, 13],
[9, 10, 13, 14],
[10, 11, 14, 15],
[0, 3, 12, 15]
];
for (let i = 0; i < lines.length; i++) {
const [a, b, c, d] = lines[i];
if (
squares[a] &&
squares[a] === squares[b] &&
squares[a] === squares[c] &&
squares[a] === squares[d]
) {
return squares[a];
}
}
return null;
}
function Square(props) {
return (
<button className="square" onClick={props.onClick} style={props.style}>
{props.value}
</button>
);
}
ReactDOM.render(<Game />, document.getElementById('root'));
答案 0 :(得分:0)
好,通过创建一个填充颜色的并行数组解决了这个问题,这样我们就可以使用正确的颜色回到过去。