在JavaScript中为网址创建动态变量

Question

我当前的变量'theurl'具有给定的静态URL。我想通过变量传递URL。主要问题是我想要的URL是通过在单独的网站上输入值来创建的。有没有办法以这种方式检索URL还是完全可怕？

我要从中检索生成的URL的网站是https://cloud.timeedit.net/ltu/web/schedule1/ri1Q7.html#

从那里我在下拉菜单旁边的搜索字段中输入代码“ A0033H”，并选择了“ kurs / program”（瑞典语）。

此刻，我已经检查出两个html页面之间的传递值。

<script type="text/javascript">
        var HttpClient = function () {
            this.get = function (aUrl, aCallback) {
                var anHttpRequest = new XMLHttpRequest();
                anHttpRequest.onreadystatechange = function () {
                    if (anHttpRequest.readyState == 4 && anHttpRequest.status == 200)
                        aCallback(anHttpRequest.responseText);
                }
                anHttpRequest.open("GET", aUrl, true);
                anHttpRequest.send(null);
            }
        }



        var theurl = 'https://cloud.timeedit.net/ltu/web/schedule1/ri166XQ2505Z5YQv250132Z6yQY820653YX5Y3gQ3076757.json';
        var client = new HttpClient();
        client.get(theurl, function (response) {
            var response1 = JSON.parse(response);
            //alert(response);

            var test = JSON.stringify(response);

            var test2 = test.replace(/,/g, "  ");
            var test3 = test2.replace(/}/g, " ");
            var test4 = test3.replace(/{/g, " ");
            var test5 = test4.replace(/"/g, " ");
            var test6 = test5.replace(/ /g, " ");
            var test7 = test6.replace(/\\/g, " ");
            var test8 = test7.replace(/ \ /g, " ");
            var test9 = test8.replace(/\ /g, " ");
            var test10 = test9.replace(/]/g, " ");
            var test11 = test10.replace(/\[/g, " ");
            var test12 = test11.replace(/"  "/g, '');


            //alert(test12);

            // this is the string variable
            var wordLength = test12.length; // we use the length method to store the length of the word string in a variable

            document.write('<table>');
            document.write('<tr><th>Lektioner</th></tr>');



            for (i = 0; i < wordLength; i++) {

                var indexNr = test12.indexOf('id', i += 100);
                var indexNr2 = test12.indexOf('id', i += 200);
                //alert(indexNr);
                //alert(indexNr2);

                var substring = test12.substring(indexNr, indexNr2);
                // alert(substring);
                var j = 200;
                var indexNr4 = test12.indexOf('columns', j += 110);
                var indexNr3 = test12.indexOf('id', j += 110);
                var substring2 = test12.substring(indexNr4, indexNr3);

                document.write('<tr><td>' + substring + '</td></tr>');
            }
            document.write('</table>');
        });
    </script>

产生的结果为我提供了在表中构造为字符串的JSON格式。

我知道这是严格的意大利面条式代码，但是我只是想知道是否可以检索URL？