django.db.utils.OperationalError: foreign key mismatch in Shell command forloop

时间:2019-01-07 13:56:46

标签: django django-models django-shell

I am working on the following two Django models:

Organisation model which has the User as Foreign key and the Category list which has the Organisation as its Foreign Key

Following are the Models:

# Create your models here.
from django.contrib.auth.models import User
from django.db import models

class Organisation(models.Model):
  user = models.ForeignKey(
    User, 
    on_delete=models.CASCADE,
    null=True
  )
  organisation_name = models.TextField(
    primary_key=True,
    blank=True
  )

  def __str__(self):
    return self.organisation_name


class Category(models.Model):

  # renamed organisation to organisation_name

  organisation_name = models.ForeignKey(
    Organisation, 
    on_delete=models.SET_NULL, 
    null=True
  )
  category = models.TextField(
   blank=True,
   max_length=200
  )

  class Meta:
    verbose_name_plural = 'Category'

Now I have got a huge list of 150+ values stored in my settings.py file which I want to add within the Category model.

The CATEGORY_LIST = ['value', 'value2', ...., 'valueN'] looks like this

This is the script I am executing in shell:

from Venter.models import Organisation, Category
from Backend import settings

cat_list = settings.CATEGORY_LIST # the list is getting loaded into cat_list
org_name = Organisation.objects.get(organisation_name='ABC') # exists
for x in cat_list:
    Category.objects.create(organisation=org_name, category=x)

However I am encounter the following error:

 django.db.utils.OperationalError: foreign key mismatch - "Mysite_category" referencing "Mysite_organisation"

where: Mysite is my app name in Django project.

Please help! Thanks

UPDATE: Solution:

The Python interpreter was incorrectly referencing the 'Organisation' model and not the 'organisation' field of the 'Category' model, it was a naming convention problem. I have now resolved it

2 个答案:

答案 0 :(得分:0)

(代表问题作者发布的解决方案)

Python解释器错误地引用了“组织”模型而不是“类别”模型的“组织”字段,这是一个命名约定问题。我现在已经解决了

答案 1 :(得分:0)

<块引用>

Mysite_category 的 id 没有 PK。 第二个表 Mysite_organisation 相同。

CREATE TABLE "Mysite_category" (
"id"    integer NOT NULL,
"name"  varchar(255) NOT NULL,
"description"   text NOT NULL,
PRIMARY KEY("id" AUTOINCREMENT)
);
<块引用>

关注 id 并且相同的查询将用于第二个表。 这并不重要,您必须通过此查询将 id 设为主键。有很多选择可以做到这一点。把id设为PK就好了。