我致力于角度5和定调。我的项目页面有2个p-dropdown
,要求是,如果car dropdown
中的标签为'Others'
,则在第二个下拉列表中添加一个名为'No Paint'
的选项,并且如果{{1} }下拉标签不是car
从第二个下拉列表中删除'Ohters'
选项。我一直在动态地添加和删除下拉菜单选项。谁能指导,下面是我的代码。谢谢
'No Paint'
型号:DropDownOptions.ts
Car: <p-dropdown [options]="cars" [(ngModel)]="selectedCar" [filter]="true"></p-dropdown>
<p-dropdown [options]="paints" [(ngModel)]="selectedPaint" [filter]="true"></p-dropdown>
constructor() {
this.cars= [
{name: 'AA', code: 'aa'},
{name: 'BB', code: 'bb'},
{name: 'CC', code: 'cc'},
{name: 'DD', code: 'dd'},
{name: 'Others', code: 'others'}
];
this.paints= [
{name: 'XX', code: 'xx'},
{name: 'YY', code: yyb'},
{name: 'ZZ', code: 'zz'}
];
我确实尝试过export class DropDownOptions {
label: string;
value: string
}
,但这会在我更改下拉列表值时多次添加“其他”选项。
答案 0 :(得分:1)
这应该很简单。在第一个p下拉(汽车)事件(onChange)
<p-dropdown [options]="cars"
(onChange)="checkIfOther($event)"
[(ngModel)]="selectedCar"
[filter]="true"></p-dropdown>
.ts:
checkIfOther(event){
if(event.value.code === 'others'){
this.paints.find(paint => paint.code == 'No Paint') === undefined ? this.paints.push({name:'No paint', code: 'No Paint'}) : null;
}
else{
let idx = this.paints.findIndex(paint => paint.code == 'No Paint';
idx != undefined ? this.paints.slice(idx,1) : null;
}
答案 1 :(得分:0)
我使用ES6进行了以下操作:
if(event.value.code === 'others'){
this.paints.find(paint => paint.code == 'No Paint') === undefined ? this.paints.push({name:'No paint', code: 'No Paint'}) : null;
}
else{
this.paints = this.paints.filter(e => e !== 'Others') //remove 'Others'
}