Question

我有一个LoanWithClient继承自Loan的模型：

public class LoanWithClient : Loan
{
    public Client Client { get; set; }
}

如何访问整个继承的Loan对象，而不必显式地编写其属性？

LoanWithClient不包含贷款的定义

return new LoanWithClient
{
     **Loan** = loan, //The Loan is erroring: LoanWithClient does not contain a definition for Loan
     Client = client
};

分类贷款：

public class Loan
{
    public int ID { get; set; }
    public string Address { get; set; }
    public string City { get; set; }
    //etc..
}

Answer 1

类LoanWithClient继承自Loan。这意味着子类具有父类的所有属性。但这并不意味着子类包含父类作为属性。您可以像这样编写类-

public class Loan
{
    public int ID { get; set; }
    public string Address { get; set; }
    public string City { get; set; }
    //etc..
}

public class LoanWithClient
{
    public Loan Loan { get; set; }
    public Client Client { get; set; }
}

return new LoanWithClient
{
     Loan = loan,
     Client = client
};

如果要保留您的类体系结构，可以按照以下方式返回-

return new LoanWithClient
{
     ID = loan.ID,
     Address = loan.Address,
     City = loan.City,
     //etc..
     Client = client
};

Answer 2

您要

访问继承的成员

贷款不是成员，而是父母。像这样访问贷款的成员：

return new LoanWithClient
{
     ID = loan.ID,
     Address = loan.Address,
     City = loan.City,
     //etc...
     Client = client
};

访问继承的成员

2 个答案: