根据this answer,PowerShell语句可以用分号分隔。
以下是我正在使用的脚本的摘要(为简化起见,已进行了部分编辑):
Add-Type -AssemblyName System.Web;
$server = "http://website.com/index.php";
foreach ($path in [System.IO.Directory]::EnumerateFiles("C:\path\to\dir","*.xml","AllDirectories")) {
try {
$oXml = New-Object System.XML.XMLDocument;
$oXml.Load($path);
<more commands here>;
} catch {}
}
这是我进行压缩的众多尝试之一:
powershell -ExecutionPolicy Bypass -Command "Add-Type -AssemblyName System.Web; $server = 'http://website.com/index.php'; foreach ($path in [System.IO.Directory]::EnumerateFiles("C:\path\to\dir","*.xml","AllDirectories")) { try { $oXml = New-Object System.XML.XMLDocument; $oXml.Load($path); <more commands here>;} catch {}}"
这是cmd返回的错误:
At line:1 char:140
+ ... hp'; foreach ($path in [System.IO.Directory]::EnumerateFiles(C:\path ...
+ ~
Missing ')' in method call.
At line:1 char:140
+ ... ry]::EnumerateFiles(C:\path\to\dir,*.xml,A ...
+ ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
Unexpected token 'C:\path\to\dir' in expression or statement.
At line:1 char:140
+ ... hp'; foreach ($path in [System.IO.Directory]::EnumerateFiles(C:\path ...
+ ~
Missing closing ')' after expression part of foreach loop.
At line:1 char:181
+ ... y]::EnumerateFiles(C:\path\to\dir,*.xml,Al ...
+ ~
Missing argument in parameter list.
At line:1 char:202
+ ... \path\to\dir,*.xml,AllDirectories)) { try ...
+ ~
Unexpected token ')' in expression or statement.
At line:1 char:203
+ ... path\to\dir,*.xml,AllDirectories)) { try { ...
+ ~
Unexpected token ')' in expression or statement.
+ CategoryInfo : ParserError: (:) [], ParentContainsErrorRecordException
+ FullyQualifiedErrorId : MissingEndParenthesisInMethodCall
如何(正确)将以上PowerShell脚本压缩为一行?
答案 0 :(得分:4)
Nicole,您在这里有两个选择。
首先类似于您现在使用的技术,但是用单引号替换脚本中的任何双引号。将整个脚本用与号和方括号括在双引号中。这会给你这样的东西...
powershell -ExecutionPolicy Bypass -Command "& {Add-Type -AssemblyName System.Web; $server = 'http://website.com/index.php'; foreach ($path in [System.IO.Directory]::EnumerateFiles('C:\path\to\dir','*.xml','AllDirectories')) { try { $oXml = New-Object System.XML.XMLDocument; $oXml.Load($path); <more commands here>;} catch {}}}"
第二个选择是对脚本进行base64编码,因此您不必担心脚本的复杂程度。然后使用-EncodedCommand选项启动powershell.exe。
为此,您首先需要像这样准备base64编码脚本
$Script = @'
Add-Type -AssemblyName System.Web;
$server = "http://website.com/index.php";
foreach ($path in [System.IO.Directory]::EnumerateFiles("C:\path\to\dir","*.xml","AllDirectories")) {
try {
$oXml = New-Object System.XML.XMLDocument;
$oXml.Load($path);
<more commands here>;
} catch {}
}
'@
$ByteScript = [System.Text.Encoding]::Unicode.GetBytes($Script)
[System.Convert]::ToBase64String($ByteScript)
请注意,您实际的脚本位于多行字符串文字之间,并在其周围的单独行上带有@'和'@。该命令的输出是脚本的base64编码的字符串。现在,您只需在命令行中使用它
powershell.exe -EncodedCommand "QQBkAGQALQBUAHkAcABlACAALQBBAHMAcwBlAG0AYgBsAHkATgBhAG0AZQAgAFMAeQBzAHQAZQBtAC4AVwBlAGIAOwANAAoADQAKACQAcwBlAHIAdgBlA
HIAIAA9ACAAIgBoAHQAdABwADoALwAvAHcAZQBiAHMAaQB0AGUALgBjAG8AbQAvAGkAbgBkAGUAeAAuAHAAaABwACIAOwANAAoADQAKAGYAbwByAGUAYQ
BjAGgAIAAoACQAcABhAHQAaAAgAGkAbgAgAFsAUwB5AHMAdABlAG0ALgBJAE8ALgBEAGkAcgBlAGMAdABvAHIAeQBdADoAOgBFAG4AdQBtAGUAcgBhAHQ
AZQBGAGkAbABlAHMAKAAiAEMAOgBcAHAAYQB0AGgAXAB0AG8AXABkAGkAcgAiACwAIgAqAC4AeABtAGwAIgAsACIAQQBsAGwARABpAHIAZQBjAHQAbwBy
AGkAZQBzACIAKQApACAAewANAAoADQAKACAAIAB0AHIAeQAgAHsADQAKACAAIAAgACAAJABvAFgAbQBsACAAPQAgAE4AZQB3AC0ATwBiAGoAZQBjAHQAI
ABTAHkAcwB0AGUAbQAuAFgATQBMAC4AWABNAEwARABvAGMAdQBtAGUAbgB0ADsADQAKACAAIAAgACAAJABvAFgAbQBsAC4ATABvAGEAZAAoACQAcABhAH
QAaAApADsADQAKACAAIAAgACAAPABtAG8AcgBlACAAYwBvAG0AbQBhAG4AZABzACAAaABlAHIAZQA+ADsADQAKACAAIAB9ACAAYwBhAHQAYwBoACAAewB
9AA0ACgANAAoAfQA="
唯一的主要缺点是Base64编码的字符串大于原始字符串。
答案 1 :(得分:1)
使用"
代替C:\>powershell -Command "echo "Hello, World!"; echo "Hello, World!""
Hello
World!
Hello
World!
,或者您需要转义引号:
echo Hello, World!
Powershell将其视为C:\>powershell -Command "echo \"Hello, World!\"; echo \"Hello, World!\""
Hello, World!
Hello, World!
,它将每个单词打印在单独的行上。现在我们转义引号:
echo "Hello, World!"
Powershell将其视为powershell -ExecutionPolicy Bypass -Command "Add-Type -AssemblyName System.Web;
$server = \"http://website.com/index.php\";
foreach ($path in [System.IO.Directory]::EnumerateFiles(\"C:\path\to\dir\",\"*.xml\",
\"AllDirectories\"))
{ try { $oXml = New-Object System.XML.XMLDocument; $oXml.Load($path); <more commands here>;} catch {}}"
,这将为您提供所需的内容。
因此,您的行变成了(为了便于阅读):
Failed to convert object of type <class 'dict'> to Tensor.
但是,在这种情况下,@ Drew的评论可能是一种更好的方法...
答案 2 :(得分:1)
您没有在字符串中转义引号。因为您要以字符串形式传递命令行参数(即,双引号内),所以只要它命中下一个双引号,它就会认为这是命令的结尾。有了您所拥有的,最简单的选择是在命令中用单引号而不是双引号将引号内更改:
powershell -ExecutionPolicy Bypass -Command "Add-Type -AssemblyName System.Web; $server = 'http://website.com/index.php'; foreach ($path in [System.IO.Directory]::EnumerateFiles('C:\path\to\dir','*.xml','AllDirectories')) { try { $oXml = New-Object System.XML.XMLDocument; $oXml.Load($path); <more commands here>;} catch {}}"
您也可以只使用双双引号,即:
powershell -ExecutionPolicy Bypass -Command "Add-Type -AssemblyName System.Web; $server = ""http://website.com/index.php""; foreach ($path in [System.IO.Directory]::EnumerateFiles(""C:\path\to\dir"",""*.xml"",""AllDirectories"")) { try { $oXml = New-Object System.XML.XMLDocument; $oXml.Load($path); <more commands here>;} catch {}}"
还有其他逃生方式,但是其中任何一种都可以满足您的需求。
答案 3 :(得分:1)
关键是确保您在powershell命令中坚持双引号。例如。
Powershell.exe -Command "foobar"
然后,命令中的所有内容都应使用单引号。例如。
Powershell.exe -Command "Write-Host 'foobar'"
有时您最终不得不在单引号内重用双引号,因此可以通过使用转义符(\)来解决此问题。例如。
Powershell.exe -Command "Write-Host \"foobar\""
或者使用双引号(“”)进行转义。例如。
Powershell.exe -Command "Write-Host ""foobar"""
最后,当命令中的内容变得棘手时,您还可以使用重音符转义符(`)。例如。
Powershell.exe -Command "Write-Host `'foobar`'"
我希望这会有所帮助。
答案 4 :(得分:1)
我认为this is是最简单,最清晰的方法,因为它不需要任何多余的切换;只是普通的PowerShell代码:
PowerShell ^
Add-Type -AssemblyName System.Web; ^
$server = \"http://website.com/index.php\"; ^
foreach ($path in [System.IO.Directory]::EnumerateFiles(\"C:\path\to\dir\",\"*.xml\",\"AllDirectories\")) { ^
try { ^
$oXml = New-Object System.XML.XMLDocument; ^
$oXml.Load($path); ^
<more commands here>; ^
} catch {} ^
}
%End PowerShell%
只需在每行末尾添加一个^
,并用反斜杠将每个引号转义。
这种方式比很长的一行更具可读性 ...