Question

我正在尝试从json src获取最小和最大温度值。我没有得到想要的结果。这就是我到目前为止所拥有的。

非常感谢您的帮助

<?php  

$url = 'https://samples.openweathermap.org/data/2.5/forecast?id=524901&appid=b6907d289e10d714a6e88b30761fae22'; 
$data = file_get_contents($url); 
$forecasts = json_decode($data); 
$length = count($forecasts->list);

    for ($i = 0; $i < $length; $i++) {
        $val = round($forecasts->list[$i]->main->temp, 0);
    }       

    $min = min($val);
    $max = max($val);

    echo "max: ". $max ." - min: ". $max;

?>

Answer 1

通过$val循环的每一遍都将覆盖for的值。您实际要做的是将每个值推入一个数组，然后可以取最小值和最大值：

$val = array();
for ($i = 0; $i < $length; $i++) {
    $val[] = round($forecasts->list[$i]->main->temp, 0);
}       

$min = min($val);
$max = max($val);

Answer 2

好，所以我假设“ temp”是您要获取最小/最大的属性：

<?php

function max($list){
    $highest = $list[0]->main->temp;
    foreach($list as $l){
        $highest = $l->main->temp > $highest ? $l->main->temp : $highest;
    }
    return $highest;
}

function min($list){
    $lowest = $list[0]->main->temp;
    foreach($list as $l){
        $lowest = $l->main->temp < $lowest ? $l->main->temp : $highest;
    }
    return $lowest;
}

$url = 'https://samples.openweathermap.org/data/2.5/forecast?id=524901&appid=b6907d289e10d714a6e88b30761fae22'; 
$data = file_get_contents($url); 
$forecasts = json_decode($data); 
$length = count($forecasts->list);    

$min = min($forecasts->list);
$max = max($forecasts->list);

echo "max: ". $max ." - min: ". $max;

?>

应根据您的情况复制粘贴...

使用PHP从json文件获取最大值/最小值

2 个答案: