Question

我试图跟踪一个人从两个日期可以输入的餐点，您可以从DateTimePickers输入。

每天之间的特定时间之间有三顿饭：

6-8AM餐1
下午12点至下午2点用餐2
5-7PM膳食3

如果某人在某个特定时间之后到达，他们会错过一顿饭，例如，如果我在2018年1月1日凌晨3点到达，而在2018年1月2日下午2点离开，我将只收到5顿饭，因为我错过了最后一餐。

这是我想出的代码，但是不幸的是，如果两个日期之间的时间间隔超过一天，我将很难编写代码。

def nearestLowerPower(a,b):
    n=1
    while True:
        n *= a
        if n > b:
            return n / a

Answer 1

我发现您的代码很难维护（如果您以后想加第四餐，更改代码将是一场噩梦），因此我为您提供了一种不同的方法，并给出了答案您的问题。

首先，我将定义一个这样的类：

然后，我将简单地实例化该类并调用函数：

public class DayMeals
{
   private int[] entryTimes = new int[] { 6, 12, 17 };
   private int[] exitTimes = new int[] { 8, 14, 19 };
   private int[] mealCounts = new int[3];
   private bool countHalfMeals = false;

   public DayMeals(bool countHalfMeals)
   {
       this.countHalfMeals = countHalfMeals;
   }

   public void AddFullDay()
   {
       mealCounts[0]++;
       mealCounts[1]++;
       mealCounts[2]++;
   }

   public void CountMealsForADay(DateTime timeArrived, DateTime timeExit)
   {
       for (int i = 0; i < mealCounts.Length; i++)
       {
           int mealEntryTime = entryTimes[i];
           int mealExitTime = exitTimes[i];
           if (timeArrived.Hour <= mealEntryTime && timeExit.Hour >= mealExitTime)
               mealCounts[i]++;
           else if (countHalfMeals && timeExit.Hour > mealEntryTime && timeExit.Hour <= mealExitTime)
               mealCounts[i]++;
       }
   }

   public void PrintMealsCount()
   {
       for (int i = 0; i < mealCounts.Length; i++)
       {
           System.Console.WriteLine($"Meal #{i + 1} count = {mealCounts[i]}");
       }
   }
}

我尝试了这段代码，它似乎按预期工作。请查看它，让我知道这是否是您想要实现的目标。

注意：我知道“ AddDays（1）”的用法是违反直觉的，因为我将第一天的同一小时保持为下一天。但是，如果您对某个人在星期一而不是星期二的11点进入这个事实不感兴趣，则用餐次数是相同的。基本上，我只是将入场时间追溯到最后一天。

Answer 2

您可以在这里循环播放。我仅通过使用标准c＃对象进一步简化了代码。诀窍是计算整天的工作时间，并计算时间跨度。

import android.os.Bundle;
import io.flutter.facade.Flutter;
import io.flutter.app.FlutterActivity;

public class MyActivity extends FlutterActivity {

    @Override
    public void onCreate(Bundle savedInstanceState) {

        // use software rendering (ideally only when you need to)
        getIntent().putExtra("enable-software-rendering", true);

        // start Flutter
        Flutter.startInitialization(this);
        super.onCreate(savedInstanceState);
    }
}

Answer 3

我还没有在VS中进行检查，但是类似的东西应该可以工作。我复制了您当天的代码，并假设它也是正确的：

public class MealCalculation
    {
        int countA, countB, countC = 0;
        int total = 0;
        public void Calculate()
        {

            var start = DateTime.Now;
            var finish = DateTime.Now;

            // Same Day
            if (start.Date == finish.Date)
            {
                MealsCalculate(start.Hour, start.Hour);
            }
            // Next Day
            else if (start.AddDays(1).Date == finish.Date)
            {
                MealsCalculate(start.Hour, 24);
                MealsCalculate(0, finish.Hour);
            }
            // Great Than 1 Day
            else
            {
                // First Day
                MealsCalculate(start.Hour, 24);

                // Middle Full Days
                var days = NumberOfDays(start.Date, finish.Date);
                countA += days;
                countB += days;
                countC += days;

                // Finish Day
                MealsCalculate(0, finish.Hour);
            }

            // Total
            total = countA + countB + countC;

        }
        public int NumberOfDays(DateTime start, DateTime finish)
        {
            var days = 0;
            while (start < finish)
            {
                start.AddDays(1);
                days++;
            }
            return days - 1;
        }


        public void MealsCalculate(int totalHoursArrived, int totalHoursExit)
        {
            if (totalHoursArrived <= 8 && totalHoursExit >= 17) //if date is before or on 8AM and leaves on or after 5PM.
            {
                countA += 1;
                countB += 1;
                countC += 1;
            }
            else if (totalHoursArrived <= 8 && (totalHoursExit >= 12 && totalHoursExit < 17)) //if date is before or on 8AM and leaves before 5PM
            {
                countA += 1;
                countB += 1;
            }
            else if (totalHoursArrived <= 8 && totalHoursExit < 12) //if date is before or on 8AM and leaves before 12PM
            {
                countA += 1;
            }
            else if ((totalHoursArrived <= 12 && totalHoursArrived > 8) && totalHoursExit >= 17) //if date is before or on 12PM and leaves on or after 5PM
            {
                countB += 1;
                countC += 1;
            }
            else if ((totalHoursArrived <= 12 && totalHoursArrived > 8) && totalHoursExit < 17) //if date is before or on 12PM and leaves before 5PM
            {
                countB += 1;
            }
            else if (totalHoursArrived >= 17) //if date is after or on 5PM
            {
                countC += 1;
            }
        }

    }

如何保持两个日期之间的特定时间之间的计数

3 个答案: