with open("bankaccount.txt", 'a+') as f:
if User1_working_status =="1":
f.write("{}\n{}\n{}\n{}\n{}\n{}\n{}\n{}\n{}\n".format("Name: " + user1_title + " " + user1_name,
"Gender:" + user1_gender,"Town and country: "
+ user1_town, "Age: " + user1_age,"Country and town of birth: "+ user1_country_of_birth,"Nationality: "
+ user1_nationality,"Country residence:"+user1_country_residence,"Tax resident country: "
+ user1_tax_res,"Working status: Employed"))
print("Working status: Employed")
elif User1_working_status=="2":
f.write("{}\n{}\n{}\n{}\n{}\n{}\n{}\n{}\n{}\n".format("Name: " + user1_title + " " + user1_name, "Gender:"
+ user1_gender,"Town and country: " + user1_town, "Age: " + user1_age,"Country and town of birth: "
+ user1_country_of_birth,"Nationality: "+ user1_nationality,
"Country residence:"+user1_country_residence,"Tax resident country: "+ user1_tax_res,
"Working status: Self Employed"))
print("Working status: Self Employed")
有没有办法缩短这个时间?我对用户2具有相同的功能,但是我必须对user2_working_status再次执行所有操作,并且由于我有9个选项,因此代码变得太长。那么,是否有办法在此代码中同时组合user1和user2?:)
答案 0 :(得分:1)
长格式字符串也非常不可读。怎么样?
with open("bankaccount.txt", 'a+') as f:
if User1_working_status in ("1", "2"):
working_status_label = "Employed" if User1_working_status == "1" else "Self Employed"
for label, value in [
("Name", user1_title),
("Gender", user1_gender),
("Town and country", user_1_town),
("Age", user1_age),
("Country and town of birth", user1_country_of_birth),
("Nationality", user1_nationality),
("Country residence", user1_country_residence),
("Tax resident country", user1_tax_res),
("Working status", working_status_label)]:
f.write("{0}: {1}\n".format(label, value))
print("Working status: {0}".format(working_status_label)
答案 1 :(得分:0)
您可以像这样为每个状态值创建带有标签的字典:
status_labels = {
"1": "Employed",
"2": "Self Employed"
}
with open("bankaccount.txt", 'a+') as f:
...
print("Working status: {}".format(status_labels[User1_working_status]))
编辑:对于多个用户,最好遍历字典列表并按照How do I format a string using a dictionary in python-3.x?使用str.format(** dict),例如像这样:
users = [{"title": "dd", "working_status": ...}, ...]
with open("bankaccount.txt", 'a+') as f:
for user in users:
..."Name: {title}, Working status: {working_status}".format(**user)