Question

我需要使用以下字符串格式将.字符替换为. \n。但是，约束是，不要仅在以下模式字符串中用.替换.\n字符。

"test was done and was negative. Urine dipstick: ph = 6\\n \\342\\200\\242 spec. Grav.  = 1.015"

我需要以下输出，例如

"test was done and was negative. \n Urine dipstick: ph = 6\\n \\342\\200\\242 spec. Grav.  = 1.015"

约束是=＆gt; "spec. Grav. = 1.015"。

Answer 1

str = "test was done and was negative. Urine dipstick: ph = 6\\n \\342\\200\\242 spec. Grav.  = 1.015"

puts str.sub('. ', ".\n") 

#=> test was done and was negative.
#=> Urine dipstick: ph = 6\n \342\200\242 spec. Grav.  = 1.015

String.sub仅替换第一个匹配。

Answer 2

str.gsub(/\.(?! (Grav| =))/, ".\n")

应该做的。

简要说明

\.匹配任何.
(?!)表示负面预测。这意味着它与这些括号中的任何内容都不匹配。
(Grav| =)因此，Grav或=之后的点将无法匹配。

Answer 3

你想要这个吗？

str.gsub(/\.(?!\n)/, "\.\n")

我们可以在gsub中使用关系运算符吗？

3 个答案:

简要说明