为什么我的printf（）语句被跳过

Question

我正在制作此比萨饼订购系统代码，客户可以在其中选择比萨饼的类型和大小，并且最多可以订购10个比萨饼。问题是程序跳过了while循环中if语句中的最后一个printf（）语句，该语句询问客户是否想要多个披萨。我没有复制所有功能，因为它确实很长代码，但如果问题可能在那里，那么我将其直接粘贴以查看。

我试图只写printf（）语句而不使用if语句，但仍然被跳过。

int main()
{

    printf("Hello! Welcome to UASKPS!\n");
    printf("You can order up to 10 pizzas.\n\n");
    printf("\nPress any key to start your order.\n");
    _getch();

    // let user order a single pizza in each loop run
    char c;
    nr_pizzas_ordered = 0;
    do
    {
        system("cls");

        // show pizza number
        printf("\nPlease choose your pizza #%d\n", nr_pizzas_ordered + 1);

        //  let user choose pizza type
        enum pizza_types desired_type = choose_pizza_type();

        //  let user choose pizza size
        enum pizza_sizes desired_size = choose_pizza_size();

        //  store the order
        all_pizza_orders[nr_pizzas_ordered].which_pizza = desired_type;
        all_pizza_orders[nr_pizzas_ordered].which_size = desired_size;

        //  one pizza has been ordered more
        nr_pizzas_ordered++;

        // ask user whether he wants to order another pizza

        if (nr_pizzas_ordered < 10)
        {
            printf("Do you want to order another pizza? (y/n)\n");
            c = _getch();
        }
        else
            c = 'n';

    } while (c == 'y');


    show_order_list();

    printf("\n\nThank you for your order! Press any key to exit.\n");
    _getch();

}