我通过regNo列连接两个表。我想在RegNo匹配的地方添加Table1.points和Table2.points的点,以防万一它不匹配,我也希望将它的点包括在列表中,如下图所示
我已经阅读了存在的问题,但没有找到解决方法,例如How can I sum columns across multiple tables in MySQL?
(
SELECT `Ex`.regNo,(`In`.`points`+`Ex`.`points`) AS 'Points'
FROM Table1`In`
LEFT JOIN Table2`Ex` ON `In`.`regNo` = `In`.`regNo`
)
UNION
(
SELECT`Ex`.regNo,(`In`.`points`+`Ex`.`points`) AS 'Points'
FROM Table1`In`
RIGHT JOIN Table2`Ex` ON `In`.`regNo` = `In`.`regNo`
);
我希望它给出按唯一(DISTINCT)regNo排列的列表
答案 0 :(得分:1)
您需要UNION
后跟GRoUP BY
:
SELECT regNo, SUM(points) AS total
FROM (
SELECT regNo, points
FROM Table1
UNION ALL
SELECT regNo, points
FROM Table2
) AS u
GROUP BY regNo
答案 1 :(得分:0)
您正在寻找两个表之间的FULL JOIN
。
SELECT
COALESCE(t1.id, t2.id) id
COALESCE(t1.regNo, t2.regNo) regNo
COALESCE(t1.points, 0) + COALESCE(t2.points 0) points
FROM
table1 t1
FULL JOIN table2 t2 on t1.regNo = t2.regNo
NB:您没有指定生成新id
的期望操作,因此默认情况下,上述查询将显示table1.id
(如果可用),否则显示table2.id
。
如果您最好生成一个新的,自动递增的字段,则:
SET @i=0;
SELECT
@i:=@i+1 id
COALESCE(t1.regNo, t2.regNo) regNo
COALESCE(t1.points, 0) + COALESCE(t2.points 0) points
FROM
table1 t1
FULL JOIN table2 t2 on t1.regNo = t2.regNo
答案 2 :(得分:0)
请检查此内容。您需要在聚合之前使用full outer join
和null替换
select
COALESCE(table1.regno, table2.regno) regno,
sum(COALESCE(table1.points,0)) + sum(COALESCE(table2.points,0)) points
from Table1
full outer join Table2
on table1.regno = table2.regno
group by
COALESCE(table1.regno, table2.regno)