Question

我正试图编写一个与教育系统有关的查询，该查询系统根据11月份在特定学校进行的以下检查类型返回数字值，只有我不太明白该怎么做。< / p>

我需要返回11月份因违规而被引用的组织列表，然后返回导致被引用的当月内的访问次数类型。我需要基于insp.Type_of_Visit__c条件的每种类型的计数，该条件基于每个提供程序，但如果有多个不合规情况，则不需要基于不同的提供程序。

我需要每种访问类型都必须包含一个单独的列。

到目前为止，我的嵌入式子查询返回未过滤的结果：

SELECT ...
, (SELECT COUNT(*) FROM Inspection__c WHERE Type_of_Visit__c = 'Pre-Licensing') AS [Number of PreLicensing Statement of Non-Compliance issue date]

那不能过滤我已有的WHERE子句。

此外，除非有更好的方法，否则我需要针对每种访问类型重复该行。

老实说，我只是想知道如何正确地做到这一点。

SELECT  a.Provider_Number__c AS [Provider ID]
, a.Provider_No__c AS [Legacy System Number]
, a.License_Status__c AS [License Status]
, a.Record_Type_Name__c AS [Record Type Name]
, a.Provider_Status__c AS [Provider Status]
, a.License_Type__c AS [License Type]
, a.Name AS [Name]
, a.Provider_Address_1__c AS [Street Address 1]
, a.Provider_Address_2__c AS [Street Address 2]
, a.Provider_city_text__c AS City
, a.Provider_Zip_Code__c AS [Zip Code]
, a.Phone
, a.Provider_Email__c AS Email
, a.Capacity__c AS [Licensed Capacity]
, insp.Date_of_Visit__c AS [Visit Date]
, inv.Statement_of_non_compliance_Issue_Date__c AS [Statement of Non-Compliance Issued Date]
    , (SELECT COUNT(*) FROM Inspection__c WHERE Type_of_Visit__c = 'Pre-Licensing') AS [Number of PreLicensing Statement of Non-Compliance issue date]

  FROM Inspection__c insp
  JOIN Account a ON a.Id = insp.Provider_No__c
  JOIN Investigation__c inv ON inv.Provider_Id__c = a.Id
  WHERE (insp.Date_of_Visit__c BETWEEN '2018-11-01' AND '2018-11-30')
  AND (a.Record_Type_Name__c = 'Large Group' OR a.Record_Type_Name__c = 'Small Group')
  AND insp.Type_of_Visit__c IN ('Pre-Licensing',
    'Provisional License 90-day Monitoring',
    'Provisional License Renewal',
    'Renewal-Monitoring',
    'Renewal-Full Review',
    'Monitoring',
    'Enhanced Monitoring',
    'Capacity Increase',
    'Change of Location',
    'Change of Space',
    'Follow-up',
    'Monitoring outside differential Licensing Cycle',
    'License Upgrade',
    'Re-Activate Provider',
    'Technical Assistance',
    'Progress',
    'Renewal-Enhanced Monitoring')

我需要计算每个提供者的每种访问类型，并将值返回到表中。如果有更好的方法，则不必是COUNT函数。

非常感谢您的帮助。谢谢。

Answer 1

如果您正在使用MySql 8，则可以使用

COUNT(*) OVER (PARTITION BY Type_of_Visit)

可能会解决您的问题。

Answer 2

我不会输入所有字符串，但我将向您展示如何进行输入。

可以说您的查询如下：

SELECT A,B,C
FROM T
WHERE Z in ('x','y','z')

其中T的索引为index1（在您的情况下，index1可能是Provider_ID）

那你就可以做到

SELECT A,B,C, G1.x_count, G1.y_count, G1.z_count
FROM T
JOIN (
  SELECT index1,
    SUM(CASE WHEN Z = 'x' THEN 1 ELSE 0 END) AS x_COUNT,
    SUM(CASE WHEN Z = 'y' THEN 1 ELSE 0 END) AS y_COUNT,
    SUM(CASE WHEN Z = 'z' THEN 1 ELSE 0 END) AS z_COUNT
  FROM T
  WHERE Z in ('x','y','z')
  GROUP BY index1
) G1 on T.index1 = G1.index1

所以现在您有了每个索引1的x，y，z计数

根据联接表条件选择COUNT（*）

2 个答案: