Question

我试图将char指针类型传递为函数的返回类型，但没有获得任何输出。这是代码：

#include<stdio.h>
#include<string.h>    
char * decrypt(char* pt)
{
    char*  result=malloc(20);
    while(*pt)
    {
    *result=*pt+3;//incrementing by 3 alphbets and copying in reslult
    pt++;
    result++;
    }
    *result='\0';
    return result;
}

int main()
{
    char plaintext[20];
    scanf("%s",plaintext);//getting input

    char *ct= decrypt(plaintext); //passing to function

    printf("\nCiphertext %s",ct);//printing reslut

}

Answer 1

list_1 = ['house','table','house'] list_2 = ['desk','computer','table'] # instantiate a dict that will contain the number of appearances in each list, as a list appearances = {} # loop through the first list for item in list_1: # If the item hasn't appeared yet, it will set the item's name as the key and [1, 0] as the value # appearances[item] is how we're going to set the key name in appearances # appearances.get(item, 0)[0] makes it so that if item is not a key in appearances, it sets the initial value at index 0 to [0, 0]. # Otherwise, it sets it to +1 of it's current value # We set appearances[item] to a list so that we can keep track of appearances in both lists # For list_1's first item, appearances would then be equal to: appearances = {'house': [1, 0]} appearances[item] = [appearances.get(item, [0, 0])[0] + 1, 0] # Do the same for the second list, but use index of 1, instead of 0 for item in list_2: # We use appearances.get() twice in case we haven't seen the item yet in either list appearances[item] = [appearances.get(item, [0, 0])[0], appearances.get(item, [0, 0])[1] + 1] # Print the result print(appearances)将在循环后指向result。

只需添加临时指针以指向字符串的开头并返回即可。

\0

旨在查找终止密码的此处代码有什么问题？

1 个答案: