Question

查询时，结果由多个值（WHILE / LOOP）组成，例如：

   $query_sku = mysqli_query($connect, "SELECT t.column_name
        FROM skus AS s
            INNER JOIN table AS t ON t.column_id = s.column_id
                WHERE s.id_sku = '{$id_sku}'");
WHILE($reg = mysqli_fetch_object($query_sku )){
  $variable = $reg->column_name;
echo "<br/">;
}

此查询/查询的结果为：

BATERIA  
PARA
CÂMERA
CANON
PowerShot ELPH 330 HS

当我将值保存在数据库中时，这些值将保存在不同的行中。

但是，我希望您将其保存为一行：

BATERIA PARA CÂMERA CANON PowerShot ELPH 330 HS

我该怎么做？谢谢！

我已经尝试这样做：

while($reg = mysqli_fetch_object($query_sku ))
    $variable .= " ".$reg->column_name;

但是，结果是重复相同的值：

PowerShot ELPH 330 HS BATTERY (RECHARGEABLE)PowerShot ELPH 330 HS BATTERY (RECHARGEABLE) CAMERAPowerShot ELPH 330 HS BATTERY (RECHARGEABLE) CAMERA CANON

Answer 1

您可以使用select直接获得结果

SELECT group_concat( t.column_name  SEPARATOR ' ')
FROM skus AS s
INNER JOIN table AS t ON t.column_id = s.column_id
WHERE s.id_sku = '{$id_sku}'

对于插入，您可以使用插入/选择

insert into my_table  (my_col)
SELECT group_concat( t.column_name  SEPARATOR ' ')
FROM skus AS s
INNER JOIN table AS t ON t.column_id = s.column_id
WHERE s.id_sku = '{$id_sku}'

无论如何，您应该查看绑定参数，并避免在SQL中使用php var（您可能会冒sqlinjectio的风险）

Answer 2

抛开代码的SQL注入漏洞。您可以将结果展平到这样的一列：

$variables = [];
while($reg = mysqli_fetch_object($query_sku)){
  $variables[] = $reg->column_name;
}

$oneColumn = implode(' ', $variables);

将来自MySQL查询的变量PHP（while / loop）的结果保存在一行中

2 个答案: