无法在REST中将字符串转换为Timespamp

时间:2019-01-04 14:50:17

标签: database hibernate datetime timestamp string-to-datetime

你好:)我真的希望我能在这里找到帮助!

问题:我使用Spring JPA,创建了基本的REST服务,添加了数据库,并且可以通过entitymanager.createQuery()在databaste中找到数据

但是当我尝试搜索时间戳或日期时间时,它给了我这个错误:

15:12   SELECT b FROM StationsMessung b WHERE b.AVNR=:AVNR AND 
b.TXNR=:TXNR AND b.DBTM=:DATUM
        java.lang.ClassCastException: java.lang.String cannot 
be cast to java.util.Date
        at org.hibernate.type.descriptor.java.JdbcTimestampTypeDescriptor.unwrap(JdbcTimestampTypeDescriptor.java:24)
        at org.hibernate.type.descriptor.sql.TimestampTypeDescriptor$1.doBind(TimestampTypeDescriptor.java:48)
        at org.hibernate.type.descriptor.sql.BasicBinder.bind(BasicBinder.java:74)
        at org.hibernate.type.AbstractStandardBasicType.nullSafeSet(AbstractStandardBasicType.java:280)
        at org.hibernate.type.AbstractStandardBasicType.nullSafeSet(AbstractStandardBasicType.java:275)
        at org.hibernate.param.NamedParameterSpecification.bind(NamedParameterSpecification.java:53)
        at org.hibernate.loader.hql.QueryLoader.bindParameterValues(QueryLoader.java:628)
        at org.hibernate.loader.Loader.prepareQueryStatement(Loader.java:2001)
        at 
org.hibernate.loader.Loader.executeQueryStatement(Loader.java:1915)
        at org.hibernate.... (show balloon)

我知道它说不能将String转换为java.util.Date,但是我不知道如何解决它。感谢每个帮助者!

///////////////////////////////////////////////// ////////// ENTITY CLASS

@Entity                                      
@IdClass(StationsMessung.class)
@Table(name = "****", schema = "***")
public class StationsMessung implements Serializable {
@Id
@GeneratedValue(strategy = GenerationType.AUTO)
@Column(name = "AVNR")
private int AVNR; ////
@Id
@GeneratedValue(strategy = GenerationType.AUTO)
@Column(name = "TXNR")
private int TXNR;
@GeneratedValue(strategy = GenerationType.AUTO)
@Temporal(TemporalType.TIMESTAMP)
@Type(type = "date")
@Column(name = "DBTM")
private Timestamp DBTM;

public StationsMessung(int AVNR, int TXNR, Timestamp DBTM) {
    this.AVNR = AVNR;
    this.TXNR = TXNR;
    this.DBTM = DBTM;    
}
public StationsMessung() {
}
public int getAvnr() {
    return AVNR;
}
public void setAvnr(int AVNR) {
    this.AVNR = AVNR;
}
public int getTxnr() {
    return TXNR;
}
public void setTxnr(int TXNR) {
    this.TXNR = TXNR;
}
public Timestamp getDBTM() {
    return DBTM;
}
public void setDBTM(Timestamp DBTM) {
    this.DBTM = DBTM;
}

///////////////////////////////////////////////// //////////// SERVICE CLASS

@Service
public class StationService {

@PersistenceContext
EntityManager entityManager;


public List<Station> getAllStationMessungen(int AVNR, int TXNR, Timestamp DATUM) { 
return entityManager.createQuery("SELECT b FROM StationsMessung b WHERE b.AVNR=:AVNR AND b.TXNR=:TXNR AND b.DBTM=:DATUM")
            .setParameter("TXNR",TXNR )
            .setParameter("AVNR",AVNR )
            .setParameter("DATUM", DATUM)
            .getResultList();
}

///////////////////////////////////////////////// ///////////// CONTROLLER CLASS

@RestController
@RequestMapping("/station")
public class StationController {
@Autowired //This annotation allows Spring to resolve and inject 
collaborating beans into your bean
StationService stationService; //service

@RequestMapping(value = "/allmessungen/{AVNR}/{TXNR}/{DATUM}", method = 
RequestMethod.GET) 
public List<Station> getAllStationMessungen(@PathVariable int AVNR, int 
TXNR, Timestamp DATUM) {
    return stationService.getAllStationMessungen( AVNR, TXNR, DATUM);
}

现在,当我搜索没有时间戳的数据时,它会向我显示数据,并且可以正常工作。

当我使用时间戳或日期时,它向我显示上面的错误。

我的输入是:

PARAM.1 AVNR:716

PARAM.2 TXNR:1339

PARAM.3 DBTM:2014-01-04 05:30:00
               (其格式为yyyy-mm-dd-hh24:mi:ss)

感谢您的帮助:)

0 个答案:

没有答案