Question

我想为每个WHERE语句获取一列，现在我必须为每个语句手动进行操作以获取结果，但是我如何立即执行呢？

SELECT 
    COUNT([ParcelEventID]) as WEEK
FROM
    [Data].[CDB].[ParcelEvent] 
WHERE
    [EventDate] BETWEEN 20180820 AND 20180826 
    --[EventDate] BETWEEN 20180827 AND 20180902
    --[EventDate] BETWEEN 20180902 AND 20180909
    --[EventDate] BETWEEN 20180909 AND 20180916
    --[EventDate] BETWEEN 20180916 AND 20180923
    --[EventDate] BETWEEN 20180923 AND 20180930
    --[EventDate] BETWEEN 20181001 AND 20181007
    --[EventDate] BETWEEN 20181008 AND 20181014 
    --[EventDate] BETWEEN 20181014 AND 20181021 
    --[EventDate] BETWEEN 20181022 AND 20181028 )
    AND [Depot] LIKE '05[12]%'
    AND [ParcelEventTypeID] = 09

编辑：感谢您的回答，他们的工作。但是，查询运行非常慢。是否可以以某种方式查询以下内容作为结果？

Eventdate ParcelEventTypeID   Count     Week 
01/12            6              10       50
01/12            8              100      50
02/12            6              25       50
02/12            8              15       50

类似这样：

SELECT week
SUM(Count)
[ParcelEventTypeID]
,datepart(weekday, [EventDateTime]) As [WeekDay]
FROM [Data].[CDB].[ParcelEvent]
GROUP BY [week], [ParcelEventTypeID]

然后得到如下结果：

Week   ParcelEventTypeID      Count
1             6                 35
1             8                 115

Answer 1

我想为每个WHERE语句获取一列

您似乎正在寻找条件聚合：

SELECT 
    SUM(CASE WHEN [EventDate] BETWEEN 20180820 AND 20180826 THEN 1 ELSE O END) AS 20180820_TO_20180826
    SUM(CASE WHEN [EventDate] BETWEEN 20180827 AND 20180902 THEN 1 ELSE 0 END) AS 20180827_TO_20180902
    ...
FROM
    [Data].[CDB].[ParcelEvent] 
WHERE
    [Depot] LIKE '05[12]%'
    AND [ParcelEventTypeID] = 09

Answer 2

您可能想要条件聚合

SELECT 
    Count(CASE WHEN [EventDate] BETWEEN 20180820 AND 20180826 THEN [ParcelEventID] end) AS WEEK1
   ,Count(CASE WHEN [EventDate] BETWEEN 20180827 AND 20180902 THEN [ParcelEventID] end) AS WEEK2
   ,Count(CASE WHEN [EventDate] BETWEEN 20180902 AND 20180909 THEN [ParcelEventID] end) AS WEEK3
   ,...
FROM
    [DATA].[CDB].[ParcelEvent] 
WHERE [EventDate] BETWEEN 20180820 AND 20181028 
  AND [Depot] LIKE '05[12]%'
  AND [ParcelEventTypeID] = 09

Answer 3

SELECT 
case 
     when [EventDate] BETWEEN 20180820 AND 20180826 then count(ParcelEventID)
     else 0 
end as 20180820_20180826,
case
     when [EventDate] BETWEEN 20180827 AND 20180902 then count(ParcelEventID) 
     else 0 
end as 20180827_20180902,
case 
     when [EventDate] BETWEEN 20180902 AND 20180909 then count(ParcelEventID) 
     else 0
end as 20180827_20180902
FROM [Data].[CDB].[ParcelEvent]
WHERE [Depot] LIKE '05[12]%' AND [ParcelEventTypeID] = 09

Answer 4

感谢您的回答，他们的工作。但是，查询运行非常慢。是否可以以某种方式查询以下内容作为结果？

Eventdate ParcelEventTypeID   Count     Week 
01/12            6              10       50
01/12            8              100      50
02/12            6              25       50
02/12            8              15       50

类似这样：

SELECT week
SUM(Count)
[ParcelEventTypeID]
,datepart(weekday, [EventDateTime]) As [WeekDay]
FROM [Data].[CDB].[ParcelEvent]
GROUP BY [week], [ParcelEventTypeID]

然后得到如下结果：

Week   ParcelEventTypeID      Count
1             6                 35
1             8                 115

在SQL的where子句中获取具有多个inbetween语句的多列

4 个答案: