当我要在页面上获取数据时,我希望页面自动重定向到另一个页面,该怎么办?我有这个代码
这是我的代码,这里是获取数据的地方,但是一旦获取,我想自动将其重定向。
<div>
<?php
$data = mysqli_query($con,"SELECT * FROM announcement");
$count = mysqli_num_rows($data);
if ($count != 0) {
//IVE ASSUMED THAT THIS WILL WORK BUT IT DIDNT
header("location:../addRedirect.php");
while($row = mysqli_fetch_array($data)) {
echo '<div id="myModal" class="modal" style="position:fixed; display: none; padding-top: 100px;
left: 0; top: 0; width: 100%; height: 100%; overflow: auto; background-color: rgb(0,0,0); background-color: rgba(0,0,0,0.9); ">
<div class="container" style="width: 100%">
<div class="card col-12" style="background-color: red; color: white;">
<div class="card-header">
<p><h3 class="text-center">Announcement</h3></p>
</div>
<div class="card-body text-center">
<h5>'.$row['additional_info'].'</h5>
<p>Please click refresh button to resume after the announcement</p>
</div>
</div>
</div>
<img class="modal-content" id="img01">
</div>';
$dataid = $row['id'];
}
}
?>
</div>
在我的第二页上,我想将其重定向回..所以当我只是获取数据时,我拥有的是自动刷新..谢谢指导我,这对我作为php和编码的起步者是一个巨大的帮助
<?php
header("location:../home.php");
?>
答案 0 :(得分:0)
如果已设置标题,则可以使用javascript而不是PHP刷新页面。
<div>
<?php
$data = mysqli_query($con,"SELECT * FROM announcement");
$count = mysqli_num_rows($data);
if ($count != 0) {
echo "<script>setTimeout(\"location.reload()\",1000);</script>";
// Other stuff ...
}
?>
</div>
如果要导航到其他页面,可以执行以下操作:
<div>
<?php
$data = mysqli_query($con,"SELECT * FROM announcement");
$count = mysqli_num_rows($data);
if ($count != 0) {
echo "<script>setTimeout(\"location.href = '../addRedirect.php';\",1000);</script>";
// Other stuff ...
}
?>
</div>
两个示例的延迟都为1秒(1000毫秒)