命令行arg不导入脚本

Question

herro，这里的菜鸟程序员正面临着两难选择，试图从终端运行一个简单的python脚本，它的运行方式完全一样

filename = test.py

from sys import argv
script, food, echo, tree=argv
print("the script is called:", script)
print("the first variable is called:", food)
print("the second variable is called:", echo)
print("blah blah third is:", tree)

（脚本结尾）

在终端

python3.7 test.py 1 2 3

当我在空闲状态下按Enter键时，我只会收到“ valueError：没有足够的值要解压）

这让我发疯了，感谢大家的帮助，谢谢！

Answer 1

它可以在Python 2-3.7中运行，但我必须进行一次更改。

更改
print("the script is called:", test.py)
到
print("the script is called:", script)

我想那可能只是一个错字。

Answer 2

这是因为参数和列表解包不匹配 试试这个

from sys import argv
# argv always take default argument as file path 
# at 0th position that is way 3+1
if len(argv) == 4:         
    script, food, echo, tree=argv
    print("the script is called:", script)
    print("the first variable is called:", food)
    print("the second variable is called:", echo)
    print("blah blah third is:", tree)

或像这样直接使用

print("the script is called:", argv[0])

Answer 3

这有效：

from sys import argv
script, food, echo, tree=argv
print("the script is called:", script)
print("the first variable is called:", food)
print("the second variable is called:", echo)
print("blah blah third is:", tree)

$ python3 ~/tmp/e test.py 1 2
the script is called: /home/bhepple/tmp/e
the first variable is called: test.py
the second variable is called: 1
blah blah third is: 2