重试时如何赋予自定义芹菜状态

Question

我有以下celery任务，我想知道任务重试时如何更改默认状态。我知道可以更改通常应在下一行self.update_state(state='MY CUSTOM STATE')中给出的状态，但是当代码重试时似乎有些不同。最后，我想将重试状态从“重试”更改为“等待”。

LOCK_EXPIRE = 60 * 2  # Lock expires in 2 minutes


@contextmanager
def memcache_lock(lock_id, oid):
    timeout_at = monotonic() + LOCK_EXPIRE - 3
    print('in memcache_lock and timeout_at is {}'.format(timeout_at))
    # cache.add fails if the key already exists
    status = cache.add(lock_id, oid, LOCK_EXPIRE)
    try:
        yield status
        print('memcache_lock and status is {}'.format(status))
    finally:
        # memcache delete is very slow, but we have to use it to take
        # advantage of using add() for atomic locking
        if monotonic() < timeout_at and status:
            # don't release the lock if we exceeded the timeout
            # to lessen the chance of releasing an expired lock
            # owned by someone else
            # also don't release the lock if we didn't acquire it
            cache.delete(lock_id)



@celery.task(bind=True, name='app.myTask1')
def myTask1(self):

    self.update_state(state='IN TASK')
    print('dir is {} '.format(dir(self)))

    lock_id = self.name
    print('lock_id is {}'.format(lock_id))

    with memcache_lock(lock_id, self.app.oid) as acquired:
        print('in memcache_lock and lock_id is {} self.app.oid is {} and acquired is {}'.format(lock_id, self.app.oid, acquired))
        if acquired:
            # do work if we got the lock
            print('acquired is {}'.format(acquired))
            self.update_state(state='DOING WORK')
            time.sleep(90)
            return 'result'

    # otherwise, the lock was already in use
    raise self.retry(countdown=60)  # redeliver message to the queue, so the work can be done later