Question

您好，我有以下代码，并被询问以下信息：演员的姓氏，按字母顺序排列，并注明参加的电影的名称以及年龄参与电影制作的时间（通常为6月30日）；

我已经尽一切方式尝试了datediff函数，但它不断给我带来错误，据我所知，我不接受以这种方式编写的生产年份。如何设置月份和日期作为查询，然后使用datediff？非常感谢您的帮助，我在浪费时间浪费我的时间。打扰一下，但我仍处于起步阶段

    create database cinema;
use cinema;
create table participation(film varchar (3) not null ,actor varchar(5) not null);
create table actor (id_actor varchar(5) not null,name varchar(30), surname varchar(30) not null);
create table film (id_film varchar(3) not null,title varchar(30) not null, kind varchar (30) not null, producer varchar (5) not null, production_year year(4));
create table producer( id_producer varchar (5) not null, name varchar (30) ,surname varchar(30) not null);
alter table producer add primary key (id_producer);
alter table film add primary key (id_film);
alter table participation add primary key (film,actor);
alter table actor add primary key (id_actor);
alter table participation add constraint fk_pfilm foreign key (film) references film(id_film);
alter table participation add constraint fk_pactor foreign key (actor) references actor(id_actor);
alter table film add constraint fk_fproducer foreign key (producer) references producer (id_producer);

insert into producer(id_producer,name,surname) values ("0000A","Steven","Spielberg"),("0000B","Stanley","Kubrick"),("0000C","Ridley","Scott");
insert into actor(id_actor,name,surname) values ("000AA","Sylvester","Stallone"),("000AB","Brad","Pitt"),
("000AC","George","Clooney"),("000AD","Demi","Moore"),("000AE","Bruce","Willis"),
("000AF","Monica","Bellucci");
insert into film(id_film,title,kind,production_year,producer) values ("00A","Jurassic Park","avventura",'2000',"0000A"),("00B","Matrix","fantascienza",'2001',"0000B"),
("00C","Star Wars","fantascienza",'2000',"0000A"),("00D","Indiana Jones","avventura",'2002',"0000B"),("00E","Rambo","avventura",'2002',"0000A"),
("00F","Rocky I","sportivo",'2001',"0000A"),("00G","Rocky II","sportivo",'2004',"0000B");
insert into participation (film,actor) values ("00A","000AA"),("00B","000AB"),("00C","000AC"),("00D","000AD"),("00E","000AA"),
("00F","000AA"),("00G","000AB"),("00A","000AC"),("00B","000AA"),("00C","000AB"),("00D","000AB");

select * from participation;
select * from actor;
select * from film;
select * from producer;

alter table actor add column datebirth date;
update actor set datebirth='1946-07-06' where id_actor="000AA";
update actor set datebirth='1963-12-18' where id_actor="000AB";
update actor set datebirth='1961-05-06' where id_actor="000AC";
update actor set datebirth='1962-11-11' where id_actor="000AD";
update actor set datebirth='1955-03-19' where id_actor="000AE";
update actor set datebirth='1964-09-30' where id_actor="000AF";


create view vista as select * from (actor inner join participation on id_actor=participation.actor);
create view vista2 as select * from (vista inner join film on vista.film=film.id_film);
select surname,title,datediff(datebirth,production_year-06-30) as età from vista2;

Answer 1

尝试将asCharBuffer()替换为：

anno_produzione-06-30

引擎可以将ISO日期表示形式转换为concat(anno_produzione, '-06-30')。

而且您不应该在字符串文字周围使用双引号。请改用单引号，这是他们在SQL中的工作。

输入带前缀年份mysql的默认月份和日期

1 个答案: