Question

我正在开发Java应用程序。我需要启用http://example.com

的CorsFilter

我正在使用此代码

<filter>
    <filter-name>CorsFilter</filter-name>
    <filter-class>org.apache.catalina.filters.CorsFilter</filter-class>
    <init-param>
        <param-name>cors.allowed.headers</param-name>
        <param-value>Accept,Accept-Encoding,Accept-Language,Access-Control-Request-Method,Access-Control-Request-Headers,Authorization,Connection,Content-Type,Host,Origin,Referer,Token-Id,User-Agent, X-Requested-With</param-value>
    </init-param>
    <init-param>
        <param-name>cors.allowed.origins</param-name>
        <param-value>*</param-value>
    </init-param>
</filter>
<filter-mapping>
    <filter-name>CorsFilter</filter-name>
    <url-pattern>https://example.com</url-pattern>
</filter-mapping>

但是我从tomcat得到错误，过滤器映射中无效的 [https://example.com]

该如何解决？注意：我也尝试过通过删除https

来example.com

如何修复tomcat的web.xml中的无效URL模式错误

0 个答案: