我有两个表:
表1:
id email
1 john@gmail.com
2 doe@gmail.com
表2:
userid key value
1 firstname john
1 phone 112233
2 firstname doe
2 phone 223344
这是无条件的mysql查询:
SELECT a.*,
b.*,
GROUP_CONCAT(b.key),
GROUP_CONCAT(b.value)
FROM table1 a
LEFT JOIN table2 b ON a.id = b.userid
这是结果:
array(
[id] => 1
[email] => john@gmail.com
[userid] => 1
[key] => firstname,phone
[value] => john,112233
)
array(
[id] => 2
[email] => doe@gmail.com
[userid] => 2
[key] => firstname,phone
[value] => doe,223344
)
这是带有条件的mysql查询:
SELECT a.*,
b.*,
GROUP_CONCAT(b.key),
GROUP_CONCAT(b.value)
FROM table1 a
LEFT JOIN table2 b ON a.id = b.userid
WHERE b.key = "firstname"
AND b.value LIKE '%jo%'
这是结果:
array(
[id] => 1
[email] => john@gmail.com
[userid] => 1
[key] => firstname
[value] => john
)
但是我想要这个:
array(
[id] => 1
[email] => john@gmail.com
[userid] => 1
[key] => firstname,phone
[value] => john,112233
)
有什么办法可以做到这一点?感谢您的帮助!
答案 0 :(得分:3)
您的查询缺少GROUP BY
子句,无法为每个用户获取一行。然后使用HAVING
子句确保聚合行包含名字 '%jo%'
:
SELECT a.*,
GROUP_CONCAT(b.key),
GROUP_CONCAT(b.value)
FROM table1 a
LEFT JOIN table2 b ON a.id = b.userid
GROUP BY a.id
HAVING sum(b.key = 'firstname'
AND b.value LIKE '%jo%') > 0;
true在MySQL中为1,在0中为false。因此,检查总和是否大于零意味着至少要检查一次该条件是否成立。