Question

我已经通过reactJS完成了渲染

render（）{

    return (
      <div>
        <Router>
          <div className="wrapper2">
            <nav id="menu-principal" className="main menu-principal">
              <ul>
                <li><NavLink className="home-link" exact to="/">início</NavLink></li>
                <li><NavLink exact to="/nota_biografica">nota biográfica</NavLink></li>

              </ul>
            </nav>
            <div className="page-content">
              <Route exact path='/nota_biografica' render={() => <NotaBiografica />} />                  
              <Route exact path='/' render={() => <Home />} />
            </div>
          </div>
        </Router>
      </div>
    )
  }

当我单击包含“家庭链接”类的链接时，我想执行一些操作。就像我在下面的示例中尝试执行的操作无效。我该如何解决？谢谢。

var el = document.querySelector(".menu-principal");
      el.onclick = (event) => {                 
        for(var i = 0; i < el.childNodes.length; i++) {
          if(el.childNodes[i].className === "home-link"){
            alert('true')
          }
        }
      }

Answer 1

由于您定位的元素是<NavLink>标签，该标签通常应导航到另一个路由器页面，所以我相信您所附加的事件将不会运行。我建议您不要使用<NavLink>，而应在this.props.history.push('/path/to/route')处理程序上使用onClick（在导航到另一个路由地址之前，需要执行这些过程之后）。

在以下示例中，请注意withRouter，我将<NavLink>更改为span，然后将onHomeCLick处理程序附加到它：

import React, {Component} from 'react';
import {withRouter, Route, BrowserRouter as Router} from "react-router-dom";
class YourComponent extends Component {

  onHomeCLick = () => {
    //DO something here prior to router navigation of ".home-link" element

    this.props.history.push( '/' );
  };

  render(){
    return (
      <div>
        <Router>
          <div className="wrapper2">
            <nav id="menu-principal" className="main menu-principal">
              <ul>
                <li><span className="home-link" onClick={this.onHomeCLick}>início</span></li>
                <li><NavLink exact to="/nota_biografica">nota biográfica</NavLink></li>

              </ul>
            </nav>
            <div className="page-content">
              <Route exact path='/nota_biografica' render={() => <NotaBiografica />} />
              <Route exact path='/' render={() => <Home />} />
            </div>
          </div>
        </Router>
      </div>
    )
  }

}

export default withRouter( YourComponent );

UPDATE ===========

如果您喜欢使用<NavLink>，这是另一个技巧，唯一的解决方法是“回叫”方式。一旦您导航到该路线，它就会触发（我仍然看不到是否有办法在导航之前进行操作）。我们开始：

import React, {Component} from 'react';
import {Route, BrowserRouter as Router} from "react-router-dom";

class YourComponent extends Component {

  isActive= (match, location) => {
    if (match) {
      console.log('Hi i am active, do something here');
    }
    return match;
  };

  render(){
    return (
      <div>
        <Router>
          <div className="wrapper2">
            <nav id="menu-principal" className="main menu-principal">
              <ul>
                <li><NavLink className="home-link" activeClassName="active" isActive={this.isActive}>início</NavLink></li>
                <li><NavLink exact to="/nota_biografica">nota biográfica</NavLink></li>

              </ul>
            </nav>
            <div className="page-content">
              <Route exact path='/nota_biografica' render={() => <NotaBiografica />} />
              <Route exact path='/' render={() => <Home />} />
            </div>
          </div>
        </Router>
      </div>
    )
  }

}

export default YourComponent;

如何在reactJs中检测包含特定类的子节点？

1 个答案: