Question

我想遍历带有未知键的字典并替换特定的子字符串值。

mydict = {
    'Getting links from: https://www.foo.com/': 
    [
        '+-BROKEN- http://www.broken.com/',
        '+---OK--- http://www.set.com/',
        '+---OK--- http://www.one.com/'
    ],
    'Getting links from: https://www.bar.com/': 
    [
        '+-BROKEN- http://www.broken.com/'
    ]
}

val = "+-BROKEN-"

for k, v in mydict.iteritems():
   if v.contains(val):
     v.replace(val, '')

我想要的结果是：

{
    'Getting links from: https://www.foo.com/':
    [
        'http://www.broken.com/',
        '+---OK--- http://www.set.com/',
        '+---OK--- http://www.one.com/'
    ], 
    'Getting links from: https://www.bar.com/': 
    [
        'http://www.broken.com/'
    ]
}

如何遍历字典并替换特定的子字符串值？

Answer 1

它无法正常工作，因为v是一个列表，而不是单个字符串。因此，v.contains(val)始终为False。完成您所描述的内容的一种方法是：

for k, v in mydict.iteritems():
  for i, s in enumerate(v):
    if val in s:
      v[i] = s.replace(val, '')

Answer 2

假设您的字典值是包含字符串的所有列表，并且您想从包含它的任何字符串中删除该值，则可以尝试：

for k, v in mydict.iteritems():
    mydict[k] = [string.replace(val,'')] for string in v]

如何遍历python字典并替换子字符串值？

2 个答案: