使用regex python和“ re”包分割字符串

Question

我在Windows 10上使用Python 3。请考虑以下字符串：

import re
s = ["12345", "67891", "01112"]

我想在3个字符处拆分这些zip以获得zip3，但是此代码引发错误。

re.split("\d{3}", s)
TypeError: cannot use a string pattern on a bytes-like object

我不太确定如何解决。帮助表示赞赏。谢谢。

Answer 1

要获取每一个的前三个，只需对它们进行字符串切片：

s = ["12345", "67891", "01112"]
first_tree = [p[0:3] for p in  s] 
print(first_tree)

输出：

['123', '678', '011'] # slicing

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要将所有文本一分为三，请将其加入，然后使用分块获取3个字母的块：

s = ["12345", "67891", "01112"]
k = ''.join(s)
threesome = [k[i:i+3] for i in range(0,len(k),3)]
print(threesome)

输出：

['123', '456', '789', '101', '112']  # join + chunking

请参见How do you split a list into evenly sized chunks?和Understanding Python's slice notation

切片和分块也适用于字符串-有关字符串的官方doku在这里：about strings and slicing

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也要获取剩余部分：

s = ["12345", "67891", "01112"]
three_and_two = [[p[:3], p[3:]] for p in s] 
print(three_and_two) #  [['123', '45'], ['678', '91'], ['011', '12']]