Question

此php文件返回Jason编码的响应。但是我的问题是，除了Jason编码解码器响应之外，它还在响应的前面加上了“ <”。Here its a picture with the response.
如何删除它？

<?php

        require 'connection.php';

      if (isset($_POST['username']) && !empty($_POST['username']) && isset($_POST['password']) && !empty($_POST['password'])) {


        $username = $_POST["username"];

        $password = $_POST["password"];



        $statement = mysqli_prepare($idCon, "SELECT * FROM user WHERE username = ? AND password = ?");

        mysqli_stmt_bind_param($statement, "ss", $username, $password);

        mysqli_stmt_execute($statement);



        mysqli_stmt_store_result($statement);

        mysqli_stmt_bind_result($statement, $user_ID, $name, $username, $password);



        $response = array();

        $response["success"] = false;  



        while(mysqli_stmt_fetch($statement)){

            $response["success"] = true;  

            $response["name"] = $name;

            $response["username"] = $username;

            $response["password"] = $password;

        }



        echo json_encode($response);
      }
      else{
        $response = array();
            $response["success"] = false;
            echo json_encode($response);
    }
    ?>

连接php文件（我将$ nameUser，$ pass，$ bazaDeDate中的日期替换为“ ***”）：

 <?php

        $nameServer="localhost"; 
        $nameUser="******";
        $pass="*****";
        $bazaDeDate="****";

        $idCon=mysqli_connect($nameServer,$nameUser,$pass);
        if(!$idCon)
            die ('Con failed');

        $rezultatSelectBD=mysqli_select_db($idCon,$bazaDeDate);
        if(!$rezultatSelectBD)
            die ('Con failed');


    ?>

Answer 1

在原始脚本中检查您的php开头标签。如果找不到错误，则将代码的各个部分一一忽略，直到找到将这个“ <”符号留下的代码为止

JSON响应中收到额外的字符

1 个答案: