我想获得动态编译代码的标准输出。
我的代码:
const otherVariableName = 0;
const variableName = otherVariableName || 1;
console.log(variableName);
form.cs的内容:
using System;
using System.Collections.Generic;
using System.Reflection;
using Microsoft.CSharp;
using System.CodeDom.Compiler;
using System.IO;
namespace ConsoleApplication2
{
class Program
{
static void Main(string[] args)
{
var source = File.ReadAllText("form.cs");
Dictionary<string, string> providerOptions = new Dictionary<string, string>
{
{"CompilerVersion", "v4.0"}
};
CSharpCodeProvider provider = new CSharpCodeProvider(providerOptions);
CompilerParameters compilerParams = new CompilerParameters
{
GenerateInMemory = true,
GenerateExecutable = false,
ReferencedAssemblies = {"System.dll" ,"mscorlib.dll"}
};
CompilerResults results = provider.CompileAssemblyFromSource(compilerParams, source);
Assembly assembly = results.CompiledAssembly;
Type program = assembly.GetType("program.TestPerson");
MethodInfo main = program.GetMethod("Main");
var outp= main.Invoke(null, null);
//Console.WriteLine(outp);
Console.ReadLine();
}
}
}
我真正想要的是在父applicaton中的变量中编译后具有form.cs(Console.WriteLine)的标准输出,顺便说一句,我不想将代码构建到文件中并作为进程运行并读取其输出。 还要假设form.cs的内容不可编辑。
答案 0 :(得分:1)
serviceHost.AddServiceEndpoint(typeof(eTutorWcfService), new NetTcpBinding(SecurityMode.None), "");
可能使您感到困惑,但是正如我在评论中所写,动态编译的代码不会在自己的进程中运行(也可以实现,但要复杂得多),因此它没有自己的输出。方法main
只是当前进程中默认AppDomain中另一个类中的另一个方法。这意味着它将写入外部 hosting 进程的控制台。您将必须使用main
捕获该输出。请参见以下linqpad代码段:
Console.SetOut
如果要写入原始标准输出,请先保存,如下所示:
string source = @"using System;
namespace program {
public class TestPerson
{
public static void Main()
{
Console.WriteLine(""TEST"");
}
}
}";
void Main()
{
Dictionary<string, string> providerOptions = new Dictionary<string, string>
{
{"CompilerVersion", "v4.0"}
};
CSharpCodeProvider provider = new CSharpCodeProvider(providerOptions);
CompilerParameters compilerParams = new CompilerParameters
{
GenerateInMemory = true,
GenerateExecutable = false,
ReferencedAssemblies = { "System.dll", "mscorlib.dll" }
};
CompilerResults results = provider.CompileAssemblyFromSource(compilerParams, source);
Assembly assembly = results.CompiledAssembly;
Type program = assembly.GetType("program.TestPerson");
MethodInfo main = program.GetMethod("Main");
var sb = new StringBuilder();
var writer = new StringWriter(sb);
Console.SetOut(writer);
var outp = main.Invoke(null, null);
sb.ToString().Dump(); // this Dump is from linqpad, do what you want with the StringBuilder content
Console.ReadLine();
}