如何将两个或多个JSON对象合并为一个JSONObject

时间:2019-01-02 10:20:49

标签: java json

我有两个如下的JSON对象

firstJSON: {"200":"success"} 
secondJSON: {"401":"not found"}

我需要使用Java将它们合并为{"codes":{"200":"success"},{"401":"not found"}}

我尝试了3种方法,但无法实现所需的输出。您能帮忙代码片段吗?

我尝试过的代码如下

JSONObject firstJSON = new JSONObject();
firstJSON.put("200", "success");
String firstJSONStr = firstJSON.toString();
System.out.println("firstJSONStr--> " + firstJSONStr);

JSONObject secondJSON = new JSONObject();
secondJSON.put("401", "not found");
String secondJSONStr = secondJSON.toString();
System.out.println("secondJSONStr--> "+secondJSONStr);

String finalJSONStr = firstJSONStr + "," + secondJSONStr;
JSONObject finalJSON1 = new JSONObject();
finalJSON1.put("codes", new JSONObject(finalJSONStr));
System.out.println("finalJSON1--> " + finalJSON1.toString());

JSONObject finalJSON2 = new JSONObject();
finalJSON2.put("codes", finalJSONStr);
System.out.println("finalJSON2--> " + finalJSON2.toString());

JSONObject finalJSON3 = new JSONObject();
ArrayList<JSONObject> jsonArray = new ArrayList<JSONObject>();
jsonArray.add(firstJSON);
jsonArray.add(secondJSON);
finalJSON3.put("codes", jsonArray);
System.out.println("finalJSON3--> " + finalJSON3.toString());

输出:

firstJSONStr--> {"200":"success"}
secondJSONStr--> {"401":"not found"}
finalJSON1--> {"codes":{"200":"success"}}
finalJSON2--> {"codes":"{\"200\":\"success\"},{\"401\":\"not found\"}"}
finalJSON3--> {"codes":[{"200":"success"},{"401":"not found"}]}

2 个答案:

答案 0 :(得分:1)

您期望的JSON {"codes":{"200":"success"},{"401":"not found"}}无效。您可以使用https://jsonlint.com/进行验证,这会产生错误:

Error: Parse error on line 4:
...00": "success"   },  {       "401": "not foun
---------------------^
Expecting 'STRING', got '{'

您最有可能希望将第一个和第二个对象归为一个数组,从而使结果低于JSON(请注意方括号[]

{"codes":[{"200":"success"},{"401":"not found"}]}

这可以通过以下方式实现:

JSONObject first = new JSONObject();
first.put("200", "success");

JSONObject second = new JSONObject();
second.put("401", "not found");

JSONArray codes = new JSONArray();
codes.put(first);
codes.put(second);

JSONObject root = new JSONObject();
root.put("codes", codes);

System.out.println(root);

答案 1 :(得分:0)

终于明白了逻辑。

            JSONObject successJSON = new JSONObject();
            successJSON.put("description", "success");

            JSONObject scJSON = new JSONObject();
            scJSON.put("200", successJSON);



            JSONObject failJSON = new JSONObject();
            failJSON.put("description","failure");


            scJSON.put("401", failJSON);


            JSONObject finalJSON = new JSONObject();
            finalJSON.put("codes", scJSON);

            System.out.println("finalJSON --> "+finalJSON.toString());