匹配列表列表的字符串并将其导出到Excel

时间:2019-01-02 07:42:36

标签: regex python-2.7

我有一个列表列表,我想按字符串“名称”和“地址”来匹配每个列表中的项目,我想将匹配的项目导出到Excel中

['Server:  Corp', 'Address:  10.17.2.5\r', '\r', 'Name:    b.resolvers.level3.net\r', 'Address:  4.2.2.2\r', '\r', ''],
['Server:  Corp', 'Address:  10.17.2.5\r', '\r', 'Name:    google-public-dns-a.google.com\r', 'Address:  8.8.8.8\r', '\r', ''],
['Server:  Corp', 'Address:  10.17.2.5\r', '\r', 'Name:    dns.quad9.net\r', 'Address:  9.9.9.9\r', '\r', '']


import re
m = re.search(r'\bName\b'| \bAddress\b', line)
for line in output:
        if m:
            print(m.group())

我想写的东西:

b.resolvers.level3.net , 4.2.2.2
google-public-dns-a.google.com , 8.8.8.8
dns.quad9.net , 9.9.9.9

1 个答案:

答案 0 :(得分:0)

尝试

IsRecording

lists=[['Server: Corp', 'Address: 10.17.2.5\r', '\r', 'Name: b.resolvers.level3.net\r', 'Address: 4.2.2.2\r', '\r', ''],['Server: Corp', 'Address: 10.17.2.5\r', '\r', 'Name: google-public-dns-a.google.com\r', 'Address: 8.8.8.8\r', '\r', ''], ['Server: Corp', 'Address: 10.17.2.5\r', '\r', 'Name: dns.quad9.net\r', 'Address: 9.9.9.9\r', '\r', '']] list2=[] for singleList in lists: list1=[] flag=0 for item in singleList: matcher=re.search('Name:(.*)', item) if matcher: list1.append(matcher.group(1).strip()) print(matcher.group(1).strip()) flag=1 if flag==1: matcher=re.search('Address:(.*)', item) if matcher: list1.append(matcher.group(1).strip()) print(matcher.group(1).strip()) list2.append(list1) import xlwt from tempfile import TemporaryFile book = xlwt.Workbook() sheet1 = book.add_sheet('sheet1') for j,a in enumerate(list2): for i,e in enumerate(a): sheet1.write(j,i,e) name = "random.xls" book.save(name) book.save(TemporaryFile()) 将成为列表列表。 list2包含

lists可以导出到excel或csv