Question

我卡在查询中，表是

TP_DEALNUM  DEALDATE    MATURITYDATE    TP_DEALTYPE     TP_NETVALUE
500         20180521    20180524        NBORR           209221500
501         20180525    20180527        NBORR           249221500
502         20180527    20180527        NBORR           747664500
601         20180530    20180531        CBORR           1000000000
602         20180530    20180531        CBORR           500000000

我的查询是如果Dealdate和MATURITYDATE之间的日期差为= 2，那么我需要

DEALDATE  TP_NETVALUE
20180525   249221500
20180526   249221500

并且如果dealdate和MATURITYDATE之间的日期差为= 3，那么我需要

DEALDATE  TP_NETVALUE
20180521   209221500
20180522   209221500
20180523   209221500

日期差将增加到14点

我在下面的查询中尝试过，但是没有得到输出

WITH cte AS (
    SELECT tp_dealnum,dealdate,  maturitydate,TP_DEALTYPE,TP_NETVALUE, 
    (maturitydate -dealdate) AS DateDiff
    FROM tablename)
    SELECT case WHEN datediff=2 THEN dealdate+1 
            WHEN datediff=3 THEN dealdate+1 END AS dealdate_1,
    tp_netvalue  FROM cte 
    WHERE  DateDiff >= 2

Answer 1

我建议在这里使用日历表方法。保留所有交易日期的记录，这些记录将填补当前表中的空白，然后加入该记录：

WITH dates AS (
    SELECT date '2018-05-01' AS DEALDATE FROM dual UNION ALL
    SELECT date '2018-05-02' FROM dual UNION ALL
    SELECT date '2018-05-02' FROM dual UNION ALL
    ....
    SELECT date '2018-05-30' FROM dual UNION ALL
    SELECT date '2018-05-31' FROM dual
)

SELECT
    d.DEALDATE,
    t.TP_NETVALUE
FROM dates d
INNER JOIN tablename t
    ON d.DEALDATE BETWEEN t.DEALDATE AND t.MATURITYDATE - 1
WHERE
    t.MATURITYDATE - t.DEALDATE BETWEEN 2 AND 3;

请注意，这只会生成丢失的数据。如果要将其合并到其他查询/逻辑中，则必须做其他工作。

Answer 2

关键是生成另一个具有这样的间歇日期的CTE-

WITH deal AS
         (SELECT 500 TP_DEALNUM,
                 20180521 DEALDATE,
                 20180524 MATURITYDATE,
                 'NBORR' TP_DEALTYPE,
                 209221500 TP_NETVALUE
            FROM dual
          UNION ALL
          SELECT 501, 20180525, 20180527, 'NBORR', 249221500 FROM dual
          UNION ALL
          SELECT 502, 20180527, 20180527, 'NBORR', 747664500 FROM dual
          UNION ALL
          SELECT 601, 20180530, 20180531, 'CBORR', 1000000000 FROM dual
          UNION ALL
          SELECT 602, 20180530, 20180531, 'CBORR', 500000000 FROM dual),
     daterange AS
         (SELECT min (dealdate) start_date, max (maturitydate) end_date
            FROM deal),
     intermittent_date AS
         (    SELECT start_date + level - 1 AS int_date
                FROM daterange
          CONNECT BY start_date + level - 1 <= end_date)
SELECT id.int_date dealdate, dl.tp_netvalue
  FROM deal dl
       INNER JOIN intermittent_date id
           ON id.int_date BETWEEN dl.dealdate AND dl.maturitydate - 1
 WHERE dl.maturitydate - dl.dealdate = 2;

输出：

  DEALDATE TP_NETVALUE
---------- -----------
  20180525   249221500
  20180526   249221500

如何在oracle中两列之间获取日期和金额？

2 个答案: